1)
LHS = cot(a/2) - tan(a/2)
= (1 - tan^2(a/2))/tan(a/2)
= (2-sec^2(a/2))/tan(a/2)
= 2cot(a/2) - cosec(a/2)sec(a/2)
= 2(1+cos(a))/sin(a) - 1/(cos(a/2)sin(a/2))
= 2 (1+cos(a))/sin(a) - 2/sin(a)) (product to sums)
= 2[(1+cos(a) -1)/sin(a)]
=2cot a
= RHS
2.
LHS = cot(b/2) + tan(b/2)
= [1 + tan^2(b/2)]/tan(b/2)
= sec^2(b/2)/tan(b/2)
= 1/sin(b/2)cos(b/2)
using product to sums
= 2/sin(b)
= 2cosec(b)
= RHS
Answer:
23,817$
Step-by-step explanation:
And you will have earned 13,817 in interest.
Answer:
? whattt
Step-by-step explanation:
Answer:
A) 
B) 
C) 
Step-by-step explanation:
Given the exponential expression, 
:
A) is equivalent to due to the Product Rule of exponents: 
.
Next, apply the Power-to-Power Rule of exponents: 
.
B) is equivalent to due to the Power-to-Power Rule of exponents: .
.
C) is equivalent to due to the Product-to-Power Rule of exponents: 
.
Answer:
0.346
Step-by-step explanation:
brainiest pls ty
