Answer:
![\sqrt[3]{62}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B62%7D)
is closest to 4.
Step-by-step explanation:
Our approach consist in comparing the given cubic root with respect to other two cubic roots consecutive to each other and whose result is an integer. The following condition must be satisfied:
![n < \sqrt[3]{62} < n+1](https://tex.z-dn.net/?f=n%20%3C%20%5Csqrt%5B3%5D%7B62%7D%20%3C%20n%2B1)
If 
, then the simultaneous inequation is observed:
Since 62 is closer to the upper bound, then is closest to 4.
A) √2
b) 4 √11
tip: if the surds are the same you can add and subtract the other number as normal!!
hope that helps!
Answer:
i think it is 20 percent
Step-by-step explanation:
Answer and Step-by-step explanation:
There are 3 cases we need to consider:
1. x > -7
2. x = -7
3. x < -7
<u>Case 1: x > -7</u>
If x is greater than -7, then we know that any number x + 7 will be a positive number. This is because -7 is the smallest negative number possible that will produce a non-positive number; any number greater than -7 will give a positive number in x + 7. So, the simplified expression of |x + 7| is just x + 7.
<u>Case 2: x = -7</u>
If x = -7, we know that -7 + 7 = 0, so |x + 7| when x = -7 is simply 0.
<u>Case 3: x < -7</u>
If x is less than -7, then from the argument in Case 1, we know that all numbers x + 7 will be negative. This means that when simplifying the absolute value expression, we have to switch the two terms. So, the simplified expression of |x + 7| when x < -7 is 7 + x. (Note that this isn't the same as x + 7 because here, x is <em>always </em>a negative number)
Hope this helps!
