Consider that,
x^2+4x+4 = (x+2)(x+2)
x^2+7x+10 = (x+2)(x+5)
Dividing those expressions leads to
(x^2+4x+4)/(x^2+7x+10) = (x+2)/(x+5)
The intermediate step that happened is that we have (x+2)(x+2) all over (x+2)(x+5), then we have a pair of (x+2) terms cancel as the diagram indicates (see below). This is where the removable discontinuity happens. Specifically when x = -2. Plugging x = -2 into (x+2)/(x+5) produces an output, but it doesn't do the same for the original ratio of quadratics. So we must remove x = -2 from the domain.
Answer: It would probably be 30
Step-by-step explanation:
The ratio is 10:0 , 20:10 , 30:20 , 40:30 , 50:40, 60:50 , etc…
so basically you just need to know the ratios!
Hope I could help :)
The answer is (1,-5), If you put those two on a graph, that point is where they collide.
It would be 5/6 because the denominator Is smaller than 10
can I be brainliest
Answer:
f. the sequence goes by the half of the previous number.
= 16, 8, 4, 2, 1, 1/2, 1/4, 1/8...
g. the sequence goes by adding the consecutive odd number added to the previous number.
first number= 3.
second number= 3+3
= 6
third number= 6+5
= 11
fourth number= 11+7
= 18
fifth number= 18+9
= 27
sixth number= 27+11
= 38
seventh number= 38+13
= 51, etc.
= 3, 6, 11, 18, 27, 38, 51...
