Answer:
The dimensions of the rectangular volleyball court are 60 ft x 30 ft
Step-by-step explanation:
Let
x ----> the length of rectangular volleyball court
y ---> the width of the rectangular volleyball court
we know that
The area of the rectangular volleyball court is equal to
![A=xy](https://tex.z-dn.net/?f=A%3Dxy)
![A=1,800\ ft^2](https://tex.z-dn.net/?f=A%3D1%2C800%5C%20ft%5E2)
so
----> equation A
-----> equation B
substitute equation B in equation A
![1,800=(2y)y](https://tex.z-dn.net/?f=1%2C800%3D%282y%29y)
![1,800=2y^2](https://tex.z-dn.net/?f=1%2C800%3D2y%5E2)
Solve for y
Simplify
![900=y^2](https://tex.z-dn.net/?f=900%3Dy%5E2)
take square root both sides
![y=30\ ft](https://tex.z-dn.net/?f=y%3D30%5C%20ft)
<em>Find the value of x</em>
![x=2y](https://tex.z-dn.net/?f=x%3D2y)
substitute the value of y
![x=2(30)=60\ ft](https://tex.z-dn.net/?f=x%3D2%2830%29%3D60%5C%20ft)
therefore
The dimensions of the rectangular volleyball court are 60 ft x 30 ft
Answer:
a) The estimates for the solutions of
are
and
.
b) The estimates for the solutions of
are
and
Step-by-step explanation:
From image we get a graphical representation of the second-order polynomial
, where
is related to the horizontal axis of the Cartesian plane, whereas
is related to the vertical axis of this plane. Now we proceed to estimate the solutions for each case:
a) ![4\cdot x^{2}-4\cdot x -1 = 0](https://tex.z-dn.net/?f=4%5Ccdot%20x%5E%7B2%7D-4%5Ccdot%20x%20-1%20%3D%200)
There are two approximate solutions according to the graph, which are marked by red circles in the image attached below:
,
b) ![4\cdot x^{2}-4\cdot x -1 = 2](https://tex.z-dn.net/?f=4%5Ccdot%20x%5E%7B2%7D-4%5Ccdot%20x%20-1%20%3D%202)
There are two approximate solutions according to the graph, which are marked by red circles in the image attached below:
,
These are independent events so
P(A and B) = P(A) * P(B)
Therefore
P(Both gears fail) = 0.05 * 0.08 = 0.004 or 0.4%
Answer:
y=3x+2
Step-by-step explanation: