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SashulF [63]
1 year ago
7

Solve the following equation. X cubed minus 6X squared plus 6X equals zero

Mathematics
1 answer:
anyanavicka [17]1 year ago
4 0

We have to solve this equation:

x^3-6x^2+6x=0

Third degree polynomials like this one are not easily solved, but this one has a root at x = 0. The let us factorize this polynomial as x times a second degree polynomial:

\begin{gathered} x^3-6x^2+6x=0 \\ x(x^2-6x+6)=0 \end{gathered}

Now we can find the roots of the quadratic polynomial as:

\begin{gathered} x=\frac{-(-6)\pm\sqrt[]{(-6)^2-4\cdot1\cdot6}}{2\cdot1} \\ x=\frac{6\pm\sqrt[]{36-24}}{2} \\ x=\frac{6\pm\sqrt[]{12}}{2} \\ x=\frac{6\pm\sqrt[]{4\cdot3}}{2} \\ x=\frac{6\pm2\sqrt[]{3}}{2} \\ x=3\pm\sqrt[]{3} \\ x_1=3-\sqrt[]{3} \\ x_2=3+\sqrt[]{3} \end{gathered}

Then, the solutions to the equation are:

x = 0

x = 3 - √3

x = 3 + √3

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The circumference of a cirlcle is 6π inches. What is the area of the cirlce?
dsp73

The correct answer is B.


Start from the equation for the circumference and solve it for the radius:


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8 0
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Solve by substitution. Show each step of your work. 5x + y = 15 3x + 2y = 16
uranmaximum [27]

Given equations are 5x + y = 15 and 3x + 2y = 16.

Solving first equation in the form y=mx+b,

5x + y = 15

y = -5x + 15

Substituting y= -5x+15 from first equation into second equation :-

3x + 2y = 16

3x + 2·(-5x + 15) = 16

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So final answers are x=2, y=5.

4 0
3 years ago
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