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mina [271]
3 years ago
6

6 more than 5 times a number is 26. What is the number?

Mathematics
1 answer:
lubasha [3.4K]3 years ago
4 0
Hey there!
We'll define "the number" as x. We know that "is" signifies an equals sign and therefore an equation, and we're going to be adding six to five times x. Therefore, we have:
5x + 6 = 26
Add -6 to both sides:
5x = 20
Divide both sides by 5 to get:
x = 4
So, 4 is the number.
Hope this helps!
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What is the rate of change from -1 to 4?
lana66690 [7]

Answer:

5

Step-by-step explanation:

-1+(1)= 0

0+(4)=4

1+4=5

5 0
3 years ago
A triangle has a base of x^1/3 m and a height of x^1/2 m. If the area of the triangle is 16 m^2​, what are the base and height o
Sliva [168]
Area = (base times height) / 2

Can rewrite it as

A= b * h * 1/2

16 = (x^(1/3)) * ( x^(1/2)) * (1/2))
Multiply by 2 to simplify
32 = x^(1/3) * x^(1/2)
32=x ^(5/6)
X=64

Base = 4
Height = 8

Please look below at how you multiply variables that have fractions as exponents (you need to add the exponents, common denominator and all that)

7 0
2 years ago
Note the graph of an athletes performance after finishing a triathlon. The x-axis measures time in hours, and the y axis measure
olasank [31]
The only incorrect statement is C)
The athlete was biking between [1,3] and running between [3,6]. The durations of 2 and 3 are not equal.
4 0
3 years ago
What is the sum of the measures of the interior angles of a 15-sided polygon?
AlladinOne [14]

Answer:

B. 2340

Step-by-step explanation:

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2340

3 0
3 years ago
Factorise each of the following algebraic expressions completely,
LekaFEV [45]

Answer:

see explanation

Step-by-step explanation:

(a)

Given

2k - 6k² + 4k³ ← factor out 2k from each term

= 2k(1 - 3k + 2k²)

To factor the quadratic

Consider the factors of the product of the constant term ( 1) and the coefficient of the k² term (+ 2) which sum to give the coefficient of the k- term (- 3)

The factors are - 1 and - 2

Use these factors to split the k- term

1 - k - 2k + 2k² ( factor the first/second and third/fourth terms )

1(1 - k) - 2k(1 - k) ← factor out (1 - k) from each term

= (1 - k)(1 - 2k)

1 - 3k + 2k² = (1 - k)(1 - 2k) and

2k - 6k² + 4k³ = 2k(1 - k)(1 - 2k)

(b)

Given

2ax - 4ay + 3bx - 6by ( factor the first/second and third/fourth terms )

= 2a(x - 2y) + 3b(x - 2y) ← factor out (x - 2y) from each term

= (x - 2y)(2a + 3b)

8 0
3 years ago
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