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mina [271]
3 years ago
6

6 more than 5 times a number is 26. What is the number?

Mathematics
1 answer:
lubasha [3.4K]3 years ago
4 0
Hey there!
We'll define "the number" as x. We know that "is" signifies an equals sign and therefore an equation, and we're going to be adding six to five times x. Therefore, we have:
5x + 6 = 26
Add -6 to both sides:
5x = 20
Divide both sides by 5 to get:
x = 4
So, 4 is the number.
Hope this helps!
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Black_prince [1.1K]
Well first count the shoe rental which is 4 dollars so she has 16 dollars left. We divide 16 and 5.50 and get 2.9090 meaning that she can play 2 games. Because u can’t pay for half the game so it would be 2 games.
8 0
3 years ago
Determine whether the point (1, 1) is a solution to the system of equations. Explain your reasoning in complete sentences. graph
erastova [34]
The solutions to system of equations are the point of intersection of the graphs of the equations.
The point of intersection of the graphs of the given equation is (0, 2). Therefore, point (1, 1) is not a solution to the system of equation.
6 0
3 years ago
help me find the volume and area of this figure step by step pleasefyi the answer key my teacher gave me says that the surface a
alisha [4.7K]

The volume of the shape

We have a cylinder that is cut into two. Its external radius is 5ft, while its internal radius is 4ft.

External radius = internal radius + thickness

\begin{gathered} \text{External radius = 4ft + 1ft } \\ =\text{  5ft} \end{gathered}

Internal radius = 4ft (given)

Recall that the volume(V) of a full cylinder is:

V\text{ = }\pi r^2h

Since the cylinder is cut into two, the volume(V) is:

V\text{ = }\frac{\pi r^2h}{2}

height (h) = 12ft (given)

The volume of the shape:

\begin{gathered} =\text{ Volume of cylinder with a radius of 5ft - Volume of cylinder with a radius of 4ft} \\ =\text{ }\frac{\pi\text{ }\times5^2\text{ }\times\text{ 12}}{2}\text{ - }\frac{\pi\text{ }\times4^2\text{ }\times\text{ 12}}{2} \\ =\text{ 471.239 - }301.593 \\ =169.65ft^3 \end{gathered}

5 0
9 months ago
A banner in the shape of an isosceles triangle is hung over the side of a building. The banner has a base of 30ft (at the roof),
Rashid [163]

Answer:

W = 9600000 joules

Step-by-step explanation:

From the given information:

The area of the banner = 1/2 × 30 × 20 = 300 ft²

The mass of the banner = 300 × 50 = 15000 pounds

Now; the integral for the required work is:

W = \int^h_o F \ ds

here;

h = height of the building

F = mg = 15000g

g = 32 ft/s²

Therefore;

W = \int ^h_o 15000g \ ds

W = \int ^{20}_0 \ 15000 (32)(20)

W = 9600000 joules

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2 years ago
Find the values for X<br>×^2-4=0​
EastWind [94]
Solve the equation so that the X is on a side by itself
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