Question

What equation is perpendicular to y=2x-3 and passes through (-1, 2)?

Answer 1

Answer:

$\[y=-\frac{1}{2}x+\frac{5}{2}\]$

Step-by-step explanation:

Equation of the given line: $\[y=2x-3\]$

Slope of the line = $\[2\]$

Slope of the perpendicular line = $\[-\frac{1}{2}\]$

So the equation of the perpendicular line:

$\[y=-\frac{1}{2}x+c\]$

This passes through the point (-1,2).Substituting in the equation:

$\[2=-\frac{1}{2}*(-1)+c\]$

=> $\[c=2+\frac{1}{2}\]$

=> $\[c=\frac{5}{2}\]$

So the equation of the line :

$\[y=-\frac{1}{2}x+\frac{5}{2}\]$