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3 years ago

Which equation below does the graph represent?

Mathematics

1 answer:

umka2103 [35]3 years ago

5 0

Answer:y=1/3x

Step-by-step explanation:

you know this by simply plugging in the x variable such as if you plug in the number 3, x=3 then your equation looks like y=1/3(3). when solving y=1 matching the graph.

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Find the range of the function. Use interval notation. g(x)=log↓3(x-2)

Marizza181 [45]

Answer:

10x=log6-3

Step-by-step explanation:

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2 years ago

you buy a baseball and a bat and spend $31. the bat costs $19 more than the baseball. what is the price of the baseball? What is

Morgarella [4.7K]

The bat costs $25.50 and the baseball costs $5.50

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3 years ago

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Find the slope on the graph

alukav5142 [94]

Answer:

3/1

Step-by-step explanation:

you need to count the hight of the line from the (0,2) which will be 3 and then how much of the distance of x is. I used rise over run.

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3 years ago

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A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and

nasty-shy [4]

Answer:

correct option is C) 2.8

Step-by-step explanation:

given data

string vibrates form = 8 loops

in water loop formed = 10 loops

solution

we consider mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = $\rho$

case (1)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

so here

$l = \frac{8 \lambda _1}{2}$ ..............1

$l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}$

and we know velocity is express as

velocity = frequency × wavelength .....................2

$\sqrt{\frac{Tension}{mass\ per\ unit \length }}$ = f × $\lambda_1$

here tension = mg

$\sqrt{\frac{mg}{\mu}}$ = f × $\lambda_1$ ..........................3

and

case (2)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

$l = \frac{10 \lambda _1}{2}$ ..............4

$l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}$

when block is immersed

equilibrium eq will be

Tenion + force of buoyancy = mg

T + v × $\rho$ × g = mg

and

T = v × $\rho$ - v × $\rho$ × g

from equation 2

f × $\lambda_2$ = f × $\frac{1}{5}$

$\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}$ .......................5

now we divide eq 5 by the eq 3

$\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}$

solve irt we get

$1 - \frac{\rho _{stone}}{\rho _{water}} = \frac{16}{25}$

relative density $\frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}$

relative density = 2.78 ≈ 2.8

so correct option is C) 2.8

3 0

3 years ago

20 pounds to 16 pounds is what present

ExtremeBDS [4]

Answer:

Decreased by 20%.

16 lbs is 80% of 20 lbs.

Step-by-step explanation:

$\frac{y}{100} :\frac{16}{20}$

y × 20 = 16 × 100

20y = 1600

20y ÷ 20 = 1600 ÷ 20

y = 80

100% - 80% = 20%

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3 years ago

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