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Dimas [21]
3 years ago
10

Cube-shaped blocks are packed into a cube-shaped storage container.

Mathematics
2 answers:
erma4kov [3.2K]3 years ago
8 0

Answer:

cm^3 = cube?

Step-by-step explanation:

Valentin [98]3 years ago
7 0

That is an interesting fact thank you for sharing your information

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What is the Value of “X”<br><br><br> Type answer -
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Answer: 96º

Step-by-step explanation:

the added angles of a triangle will be 180º

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Use the Distributive Property to multiply 8 and 45 in your head.
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Answer:

320+40=360

Step-by-step explanation:

8(40+5)

320+40=360

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FIRST PERSON GETS BRAINLIEST
Sunny_sXe [5.5K]
X = 61 degrees.
Find the number of degrees in a pentagon by using the following formula:
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Find the Perimeter of the figure below, composed of a rectangle and two semicircles. Round to the nearest tenths place.
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5 0
3 years ago
Let A and B be events with =PA0.7, =PB0.3, and =PA or B0.9. (a) Compute PA and B. (b) Are A and B mutually exclusive? Explain. (
kvasek [131]

Answer:

a) P(A \cup B) = P(A) +P(B) - P(A\cap B)

And if we solve for P(A \cap B) we got:

P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1

b) False

The reason is because we don't satisfy the following relationship:

P(A\cup B) = P(A) + P(B)

We have that:

0.9 \neq 0.3+0.7 =1

c) False

In order to satisfy independence we need to have the following condition:

P(A \cap B) = P(A) *P(B)

And for this case we don't satisfy this relation since:

0.1 \neq 0.7*0.3 = 0.21

Step-by-step explanation:

For this case we have the following probabilities given:

P(A) = 0.7, P(B) =0.7, P(A \cup B) =0.9

Part a

We want to calculate the following probability: P(A \cap B)

And we can use the total probability rule given by:

P(A \cup B) = P(A) +P(B) - P(A\cap B)

And if we solve for P(A \cap B) we got:

P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1

Part b

False

The reason is because we don't satisfy the following relationship:

P(A\cup B) = P(A) + P(B)

We have that:

0.9 \neq 0.3+0.7 =1

Part c

False

In order to satisfy independence we need to have the following condition:

P(A \cap B) = P(A) *P(B)

And for this case we don't satisfy this relation since:

0.1 \neq 0.7*0.3 = 0.21

4 0
3 years ago
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