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hammer [34]
3 years ago
12

EMERGENCY!!! What is the answer to this question

Mathematics
2 answers:
Karo-lina-s [1.5K]3 years ago
4 0

Answer:

108 have a wonderful day

Step-by-step explanation:

Daniel [21]3 years ago
3 0

Answer:

108

Step-by-step explanation:

The cubes has a volume 1/27 because 1/3 *1/3 *1/3 =1/27. Now we just take 4 and divide by 1/27. Which equals 108 cubes.

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Triangle MNO is rotated 180 using the origin as the center of rotation .Which sequence of transformations will produce the same
stiks02 [169]

180° rotation about the origin changes the signs of the coordinates.

(x, y) → (-x, -y)

It is a reflection over the y-axis and a reflection over the x-axis (in either order).

<em>You did not provide the options so hopefully you can figure out the answer based on the information I provided.</em>


5 0
3 years ago
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PLS HELP ME WITH 42!! (SHOW WORKKK!!!) + LOTS OF POINTS!!
spayn [35]
We can represent the cost of the notebooks with by saying 0.75n, and the cost of the pens by saying 0.55p.

0.75n+0.55p will be the total cost before tax.  Now, we need to add on tax.  Tax will be 0.0625 times the total amount, so we can represent the cost by saying 

(0.75n+0.55p) + 0.0625(0.75n+0.55p), so the answer is B.
3 0
3 years ago
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11 times 12 equals 10 plus 1 times 10 + 2 what property does this demonstrates
pochemuha
The answer is 144 but I do not know the property 
8 0
3 years ago
Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.
Mice21 [21]

Answer:

<em>LCM</em> = 8y^{4}(y+ 10)^{2}(y + 8)

Step-by-step explanation:

Making factors of 8y^{6}+ 144y^{5}+ 640y^{4}

Taking 8y^{4} common:

\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)

Using <em>factorization</em> method:

\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times  4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)

Now, Making factors of 2y^{4} + 40y^{3} + 200y^{2}

Taking 2y^{2} common:

\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)

Using <em>factorization</em> method:

\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10)        ............ (2)

The underlined parts show the Highest Common Factor(HCF).

i.e. <em>HCF</em> is 2y^{2} (y+ 10).

We know the relation between <em>LCM, HCF</em> of the two numbers <em>'p' , 'q'</em> and the <em>numbers</em> themselves as:

HCF \times LCM = p \times q

Using equations <em>(1)</em> and <em>(2)</em>: \Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times  4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times  4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)

Hence, <em>LCM</em> = 8y^{4}(y+ 10)^{2}(y + 8)

5 0
2 years ago
Please awnser and make sure it’s to
AlekseyPX

Answer:

the third one

Step-by-step explanation:

5 0
2 years ago
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