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Yuliya22 [10]
3 years ago
6

Please help ASAP I'm very confused

Mathematics
1 answer:
ololo11 [35]3 years ago
4 0

The answer is B. 3 9/20 = 3.45

because if you divide 9 by 20, that gives you 0.45. Then you add a 3.00, which equals

3.45


I hope I helped

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The points (9, 9) and (5, 1) fall on a particular line. What is its equation in slope-intercept form?
Ilia_Sergeevich [38]
Your equation would be y= 2x-9
3 0
3 years ago
Of new calculators tested,8 were defective and 42 passed inspection. What ratio compares the number of defective calculators to
sesenic [268]
The number of new calculators tested was 50 . . . 8 were bad and 42 were good.

The ratio of defective ones to new ones tested is 8:50 or 4:25 or 16% .
4 0
3 years ago
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A suit is on sale 32% off. The sale price is $221
Olegator [25]

Answer:

are you trying to get the discount amount?  or the discount off the $221 if so

$221 x .32 = $70.72 discount amount off the sale price $221 which would make the final price $150.28

Step-by-step explanation:

8 0
3 years ago
Consider functions of the form f(x)=a^x for various values of a. In particular, choose a sequence of values of a that converges
sleet_krkn [62]

Answer:

A. As "a"⇒e, the function f(x)=aˣ tends to be its derivative.

Step-by-step explanation:

A. To show the stretched relation between the fact that "a"⇒e and the derivatives of the function, let´s differentiate f(x) without a value for "a" (leaving it as a constant):

f(x)=a^{x}\\ f'(x)=a^xln(a)

The process will help us to understand what is happening, at first we rewrite the function:

f(x)=a^x\\ f(x)=e^{ln(a^x)}\\ f(x)=e^{xln(a)}\\

And then, we use the chain rule to differentiate:

f'(x)=e^{xln(a)}ln(a)\\ f'(x)=a^xln(a)

Notice the only difference between f(x) and its derivative is the new factor ln(a). But we know  that ln(e)=1, this tell us that as "a"⇒e, ln(a)⇒1 (because ln(x) is a continuous function in (0,∞) ) and as a consequence f'(x)⇒f(x).

In the graph that is attached it´s shown that the functions follows this inequality (the segmented lines are the derivatives):

if a<e<b, then aˣln(a) < aˣ < eˣ < bˣ < bˣln(b)  (and below we explain why this happen)

Considering that ln(a) is a growing function and ln(e)=1, we have:

if a<e<b, then ln(a)< 1 <ln(b)

if a<e, then aˣln(a)<aˣ

if e<b, then bˣ<bˣln(b)

And because eˣ is defined to be the same as its derivative, the cases above results in the following

if a<e<b, then aˣ < eˣ < bˣ (because this function is also a growing function as "a" and "b" gets closer to e)

if a<e, then aˣln(a)<aˣ<eˣ ( f'(x)<f(x) )

if e<b, then eˣ<bˣ<bˣln(b) ( f(x)<f'(x) )

but as "a"⇒e, the difference between f(x) and f'(x) begin to decrease until it gets zero (when a=e)

3 0
3 years ago
10.1 and 10.5 witch one is greater
OLga [1]

Answer:

10.5

Step-by-step explanation:

Because the digit at tenths place in 10.5 is greater than that of in 10.1

5 > 1

3 0
3 years ago
Read 2 more answers
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