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Zarrin [17]
4 years ago
15

What is the common ratio between successive terms in the sequence 1.5, 1.2, 0.96, 0.768

Mathematics
1 answer:
Pani-rosa [81]4 years ago
6 0

Answer:

To determine the common ratio of a geometric sequence. You just need to divide any two consecutive terms on it. You can see below that all of them have the same quotient.

1.2 / 1.5 = 0.8

0.96 / 1.2 = 0.8

0.768 / 0.96 = 0.8

.

Decimal form = 0.8

Fraction form = 4/5

.

Check:

1.5 x 0.8 = 1.2

1.5 x 4/5 = 6/5 = 1 1/5 = 1.2

Therefore, the common ratio between successive terms in the sequence? 1.5, 1.2, 0.96, 0.768 is 0.8 or 4/5.

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The correct answer is: Option 3: (hofog)(x)=\frac{x-14}{x+4}

Step-by-step explanation:

Given

f(x)=\frac{x-6}{x}\\g(x)=x+4\\h(x)=3x-2

We have to find

(hofog)(x)

This will be equal to:

h(f(g(x)))

So we have to find the composition of (fog)(x) first

(fog)(x) = f(g(x))\\=\frac{x+4-6}{x+4}\\=\frac{x-2}{x+4}

Now,

(hofog)(x)=h(f(g(x)))\\=3(\frac{x-2}{x+4})-2\\=\frac{3x-6}{x+4}-2\\=\frac{3x-6-2(x+4)}{x+4}\\=\frac{3x-6-2x-8}{x+4}\\=\frac{x-14}{x+4}

The correct answer is: Option 3: (hofog)(x)=\frac{x-14}{x+4}

Keywords: Composition, Functions

Learn more about function composition at:

  • brainly.com/question/10015690
  • brainly.com/question/10048445

#LearnwithBrainly

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For each card value, there are 4 choices of suit, of which we only pick 1, so there are \binom41 ways of picking a card of any given value. We draw 4 cards from the deck, so there are \binom41^4 possible hands in which each card has a different value.

Then there are \binom{13}4 \binom41^4 total hands in which all 4 cards have distinct values, and the probability of drawing such a hand is

\dfrac{\dbinom{13}4 \dbinom41^4}{\dbinom{52}4} = \boxed{\dfrac{2816}{4165}} \approx 0.6761

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