(5+14)*3+4/5=57 57 is the answer
Answer:
0.6
Step-by-step explanation:
Given that the spinner has 5 equal sections numbered 1 to 5.
- Total Sample Space, n(S)=5
Multiples of 2 in 1 to 5 are: {2,4}
Number less than than 3 are:{1,2}
Since we are required to find the probability of the spinner stopping on a number that is a multiple of 2 or is less than 3, we take the union of both sets.
{2,4}
{1,2} ={1,2,4}
Number of Outcomes=3
Therefore,
Probability of the spinner stopping on a number that is a multiple of 2 or is less than 3 
It's 3.
3‚354‚107
..................
The equation is y=6x-5
y-intercept:
y=6(0) -5 = -5
so ordered pair for y intercept is (0,-5)
x-intercept:
0=6x-5
x=5/6
ordered pair for x-intercept is (5/6 , 0)
so the two ordered pairs are (0,-5) and (5/6,0)