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mrs_skeptik [129]
4 years ago
5

Which symbol makes the statement true

Mathematics
2 answers:
ololo11 [35]4 years ago
6 0

Answer:

\frac{-2}{9} > -0.23  

Step-by-step explanation:

We are given the below mentioned question in the picture:

We have to compare the value of \displaystyle\frac{-2}{9}~ \& -0.23.

We have to fill in appropriate sign.

In order to do so first, we evaluate the value of given fraction \frac{-2}{9}.

It's value is -0.22222222.

If we compare both the value, then, -0.22222222 is always greater than -0.23.

Thus, the appropriate sign to fill the given blank is > as,

-0.22222222 > -0.23

jasenka [17]4 years ago
4 0
B , because -2/9 is farther away from zero than -0.23
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What’s the x-intercepts
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Last Saturday jay spent 6 hours playing games,studying, and talking with friends. He spent 2/5 of the time playing and 1/2 of th
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3 years ago
Consider the points A(5, 3t+2, 2), B(1, 3t, 2), and C(1, 4t, 3). Find the angle ∠ABC given that the dot product of the vectors B
Vilka [71]

Answer:

66.42°

Step-by-step explanation:

<u>Given:</u>

A(5, 3t+2, 2)

B(1, 3t, 2)

C(1, 4t, 3)

BA • BC = 4

Step 1: Find t.

First we have to find vectors BA and BC. We do that by subtracting the coordinates of the initial point from the coordinates of the terminal point.

In vector BA B is the initial point and A is the terminal point.

BA = OA - OB = (5-1, 3t+2-3t, 2-2) = (4, 2, 0)

BC = OC - OB = (1-1, 4t-3t, 3-2) = (0, t, 1)

Now we can find t because we know that BA • BC = 4

BA • BC = 4

To find dot product we calculate the sum of the produts of the corresponding components.

BA • BC = (4)(0) + (2)(t) + (0)(1)

4 = (4)(0) + (2)(t) + (0)(1)

4 = 0 + 2t + 0

4 = 2t

2 = t

t = 2

Now we know that:

BA = (4, 2, 0)

BC = (0, 2, 1)

Step 2: Find the angle ∠ABC.

Dot product: a • b = |a| |b| cos(angle)

BA • BC = 4

|BA| |BC| cos(angle) = 4

To get magnitudes we square each compoment of the vector and sum them together. Then square root.

|BA| = \sqrt{4^2 + 2^2 + 0^2} = \sqrt{20} = 2\sqrt{5}

|BC| = \sqrt{0^2 + 2^2 + 1^2} = \sqrt{5}

2\sqrt{5}\sqrt{5}\cos{(m\angle{ABC})} = 4

10\cos{(m\angle{ABC})} = 4

\cos(m\angle{ABC}) = \frac{4}{10}=\frac{2}{5}

m\angle{ABC} = cos^{-1}{(\frac{2}{5})}

m\angle{ABC} = 66.4218^{\circ}

Rounded to two decimal places:

m\angle{ABC} = 66.42^\circ

3 0
2 years ago
A square has a area of 81 square feet.
Setler [38]

Answer:

the side is 9 ft.

Step-by-step explanation:

7 0
3 years ago
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