The values are a = 7, b = -9, c = -18.
<u>Step-by-step explanation:</u>
The given quadratic equation is 
The general form of the quadratic equation is 
where,
- a is the coefficient of x².
- b is the coefficient of x.
- c is the constant term.
Now, you have to modify the given quadratic equation similar to the general form of quadratic equation.
So, bring the constant term 18 to the left side of the equation for equating it to zero.
⇒ 
Compare the above equation with general form
⇒ a = 7
⇒ b = -9
⇒ c = -18
Therefore, the values of a, b, and c are 7, -9 and -18.
Answer:
The equation of the line that is perpendicular to the line that passes through the point (-4, 2) is y = -9·x/5 + 18
Step-by-step explanation:
The coordinates of the point of intersection of the two lines = (5, 9)
The coordinates of a point on one of the two lines, line 1 = (-4, 4)
The slope of a line perpendicular to another line with slope, m = -1/m
Therefore, we have;
The slope, m₁, of the line 1 with the known point = (9 - 4)/(5 - (-4)) = 5/9
Therefore, the slope, m₂, of the line 2 perpendicular to the line that passes through the point (-4, 4) = -9/5
The equation of the line 2 is given as follows;
y - 9 = -9/5×(x - 5)
y - 9 = -9·x/5 + 9
y = -9·x/5 + 9 + 9
y = -9·x/5 + 18
Therefore, the equation of the line that is perpendicular to the line that passes through the point (-4, 2) is y = -9·x/5 + 18.
Answer:
Step-by-step explanation:
hello :
a(x) = 3x - 12 and b(x) = x-9, so
a[b(x)]=a(x-9) =3(x-9)-12
a[b(x)]=3x-9-12
a[b(x)]=3x+21
Ouch, kinda crippled w/o answer choices.
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</span>
4x-3y=17......(1)
5x+4y=60......(2)
Multiply equation (1) by 4 and equation (2) by 3:-
16x - 12y = 68
15x + 12y = 180
Adding these 2 equations:_
31x = 248
x = 248/31 = 8
Now substitute x = 8 in equation (1):-
4(8) - 3y = 17
32-3y = 17
-3y = -15
y = -15/-3 = 5
So solution is x=8,y=5
