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podryga [215]
4 years ago
5

Lucia and Marcus are playing a board game. They roll 2 dice (number cubes) to see who goes first. The person who rolls the highe

st sum gets to go first. If there is a tie, they each roll the dice again. Lucia went first and she rolled a 4 and a 1. Find the probability that Marcus will not get to go immediately after he rolls the dice. Show all of your work below. Express your answer as a fraction in simplest form, a decimal and a percent.
15points
Mathematics
1 answer:
yaroslaw [1]4 years ago
6 0

Ans

Step-by-step explanation:

                                   

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Is 3x+4y=7 linear or nonlinear
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Linear. It's in the form C= ax + by, so you back solve to get into the form you know is linear (y= mx + b). So using SADMEP (opposite of Pemdas) we can decide which order to solve for "Y=" in. 4y =7-3x. Y=((7-3X)/4). Y= 7/4 -3/4x. Y=-3/4x +7/4. Which is linear
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3 years ago
The product of a number and ten is twelve more than the product of the number and five-eighths.
ra1l [238]
Let the unknown number be x.

Given,

10 * x = 12 +  \frac{5}{8}  * x

10x = 12 +  \frac{5x}{8}

10x -  \frac{5x}{8} = 12

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3 0
4 years ago
A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters
In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

\Rightarrow y=\sqrt{x^2+100}

Differentiating with respect to t

\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}

\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}

Since the car driving towards the intersection at 13 m/s.

so,\frac{dx}{dt}=-13

\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)

Now

\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)

               =\frac{24\times (-13)}{\sqrt{676}}

               =\frac{24\times (-13)}{26}

               = -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

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