Answer:
So we have this equation:
2 (3x-2) - 4x = 5x + 2
You can first operate the parenthesis, knowing that a(b+c) = ab + ac (conmutative)
2(3x-2) - 4x = 5x + 2
2 * 3x - 2 * 2 - 4x = 5x + 2
6x - 4 -4x = 5x + 2
Now, we can operate the x:
6x - 4 -4x = 5x + 2
2x - 4 = 5x + 2
And sum 4 in both sides and substract 5x in both too.
2x - 4 = 5x +2
2x - 4 + 4 - 5x' = 5x + 2 + 4 -5x
Now we can operate:
-3x = 6
And we can divide by -3 the two sides...
x = 6/-3 = -2
Answer:
a1=2 and r=-1
Step-by-step explanation:
Given
geometric series= 2-2+2-2+2
geometric sequence has a constant ratior r and is given by
an=a1r(r)^(n-1)
where
an=nth term
r=common ratio
n=number of term
a1=first term
In given series:
r= a(n+1)/an
= a(2)/a1
= -2/2
=-1
so a1=2 and r=-1 !
X will be your answer because 6X3X7=126=X 11X2X5=110=y, X>Y. Brainliest?
There is no width to begin with.
