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MArishka [77]
3 years ago
12

Is 3x+4y=7 linear or nonlinear

Mathematics
1 answer:
Sloan [31]3 years ago
3 0
Linear. It's in the form C= ax + by, so you back solve to get into the form you know is linear (y= mx + b). So using SADMEP (opposite of Pemdas) we can decide which order to solve for "Y=" in. 4y =7-3x. Y=((7-3X)/4). Y= 7/4 -3/4x. Y=-3/4x +7/4. Which is linear
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PLEASE HELP ME !!!
vfiekz [6]

Answer:

-0.4 or 2.3

Step-by-step explanation:

simple

each box is 0.1 unit

7 0
3 years ago
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How do you solve 3x^6- 39x^4+ 108x^2= 0
ArbitrLikvidat [17]
You can first take out an x^2 from each number , 3x^6 - 39x^4 + 108x^2 = x^2 ( 3x^4 - 39x^2 + 108) Then just factor and solve for the zero's of the equation
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The nth term of a sequence is 2n2² - 4n+4 Work out the 8th term of the sequence. 8th term= Submit Answer Skip for Now​
Marrrta [24]

The nth term of a sequence exists 2n2² - 4n+4 is 36.

<h3>What is PEMDAS' order of operations?</h3>

The order of operations exists as a rule that describes the right sequence of measures for estimating a math expression. We can recognize the order utilizing PEMDAS: Parentheses, Exponents, Multiplication, and Division (from left to right), Addition, and Subtraction (from left to right).

$2*8*2^{2}  - 4*8+4

Follow the PEMDAS order of operations

Calculating the exponents, we get 2² = 4

= 2*8*4 - 4*8+4

= 64-32 +4

= 36

Therefore, the nth term of a sequence that exists 2n2² - 4n+4 is 36.

To learn more about sequences refer to:

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2 years ago
At which values of x does the function F(x) have a vertical asymptote? Check all that apply. F(x)=2/3x(x-1)(x 5).
Alekssandra [29.7K]

The function F(x) have a vertical asymptote at x =0 and x =1.

Given that

The given Function;

\rm  F(x)=\dfrac{2}{3x(x-1)(x^ 5)}

We have to determine

At which value the function F(x) has a vertical asymptote.

According to the question

The given Function;

\rm  F(x)=\dfrac{2}{3x(x-1)(x^ 5)}

The function is undefined when the denominator becomes 0. Find values of x for which the denominator is 0:

Then,

\rm 3x (x-1) (x^5)= 0

\rm x^5 =0, \ \  x=0\\\\ x-1 = 0, \ \ x =1\\

The value of x is 0 and 1.

Hence, the function F(x) have a vertical asymptote at x =0 and x =1.

To know more about Parabola click the link given below.

brainly.com/question/12868913

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A messenger entered a building on the ground
sp2606 [1]
He first travels 15 floors. He then travels 12 floors, to get to the 3rd floor. He finally travels 35 floors, for a total of 62 floors.
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