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2 years ago

13

I need help please hurryy!!

1 answer:

Lapatulllka [165]2 years ago

7 0

Answer:

y=13x

y=12.75x

Step-by-step explanation:

relationship B is being payed 12.50/hr. so if relationship A has a greater range than relationship B, your answers would be the one's that are more than 12.50.

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Is the answer option c?

Masja [62]

Answer:

Discrete

Step-by-step explanation:

A set can simply be defined as a list of values. There are many different types of sets, some are intervals, others are enumerated numbers. Often, a set composed of values that are listed is referred to as a discrete set. Discrete sets can be a list of information, or "isolated points". Knowing this information, the most logical answer to fill in the blank is "discrete".

"If a set is made up of isolated points and can be written as a list, it is called a <u>discrete</u> set."

7 0

2 years ago

Reasoning If 1/2 of 1 is 1/2 what is 1/2 of 2,3 and 4

hichkok12 [17]

Answer:

half of 2 is 1, half of 3 is 1.5,half of 4 is 2.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

The liquid base of an ice cream has an initial temperature of 86°C before it is placed in a freezer with a constant temperature

Karolina [17]

The temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

From Newton's law of cooling, we have that

$T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$

Where

$(t) = \ time$

$T_{(t)} = \ the \ temperature \ of \ the \ body \ at \ time \ (t)$

$T_{s} = Surrounding \ temperature$

$T_{0} = Initial \ temperature \ of \ the \ body$

$k = constant$

From the question,

$T_{0} = 86 ^{o}C$

$T_{s} = -20 ^{o}C$

∴ $T_{0} - T_{s} = 86^{o}C - -20^{o}C = 86^{o}C +20^{o}C$

$T_{0} - T_{s} = 106^{o} C$

Therefore, the equation $T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$ becomes

$T_{(t)}=-20+106 e^{kt}$

Also, from the question

After 1 hour, the temperature of the ice-cream base has decreased to 58°C.

That is,

At time $t = 1 \ hour$ , $T_{(t)} = 58^{o}C$

Then, we can write that

$T_{(1)}=58 = -20+106 e^{k(1)}$

Then, we get

$58 = -20+106 e^{k(1)}$

Now, solve for $k$

First collect like terms

$58 +20 = 106 e^{k}$

$78 =106 e^{k}$

Then,

$e^{k} = \frac{78}{106}$

$e^{k} = 0.735849$

Now, take the natural log of both sides

$ln(e^{k}) =ln( 0.735849)$

$k = -0.30673$

This is the value of the constant $k$

Now, for the temperature of the ice cream 2 hours after it was placed in the freezer, that is, at $t = 2 \ hours$

From

$T_{(t)}=-20+106 e^{kt}$

Then

$T_{(2)}=-20+106 e^{(-0.30673 \times 2)}$

$T_{(2)}=-20+106 e^{-0.61346}$

$T_{(2)}=-20+106\times 0.5414741237$

$T_{(2)}=-20+57.396257$

$T_{(2)}=37.396257 \ ^{o}C$

$T_{(2)} \approxeq 37.40 \ ^{o}C$

Hence, the temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

Learn more here: brainly.com/question/11689670

6 0

2 years ago

Read 2 more answers

Triangles ABC and XYZ are shown below. A student knows that AX and 2cm 22. The student claims that AABC is similar to AXYZ

bezimeni [28]

sorry i couldn't answer tho

7 0

3 years ago

I need some serious help rn, i got stuck

nordsb [41]

Answer:

I think it is add 11 both sides? If it is wrong i am sooooo sorry

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers