Two containers, A and b begin with equal volumes of liquid. 120 mL is then poured from a to B. Container b now contains four tim
2 answers:
Answer:
Step-by-step explanation:
Alright, lets get started.
Suppose A and B , both has initial volume, say x
120 ML is poured from B to A, then new volumes of A and B will be:
new volume of A
new volume of B
Volume of B is now four times volume of A, then
So, the initial volume of A and B containers is 200
So, at the end, volume of container A =
Hence the answer is 80 : Answer
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Answer:
a) 108 people with a standard deviation of 3.286335
b) No
c) 0.218163 or around 21.82%
d) See explanation below.
Step-by-step explanation:
This situation can be modeled with the Binomial Distribution which gives t<em>he probability of an event that occurs exactly k times out of n, and is given by </em>
<em>
</em>
<em>where </em>
<em>= combination of n elements taken k at a time.
</em>
<em>p = probability that the event (“success”) occurs once </em>
<em>q = 1-p </em>
In this case, the event “success” is finding an American adult who had chickenpox before adulthood with probability p=0.9
and n=120 American adults in the sample.
The <em>standard deviation for this binomial distribution</em> is
where <em>n is the sample size 120 </em>
a)
We consider a random sample of 120 American adults. How many people in this sample would you expect to have had chickenpox in their childhood?
If about 90% of American adults had chickenpox before adulthood, we expect to find 90% of 120 = 0.9*120=108 people in the sample who had chickenpox in their childhood.
The standard deviation would be
b)
Would you be surprised if there were 105 people who have had chickenpox in their childhood?
No, because 105 and 108 are in the interval [mean - s, mean +s]
c)
What is the probability that 105 or fewer people in this sample have had chickenpox in their childhood?
The probability that 105 or fewer people in this sample have had chickenpox in their childhood is
We compute this value easily with a spreadsheet and we get
d)
How does this probability relate to your answer to part (b)?
A binomial distribution with np>5 and nq>5 with n the sample size as is the case here, behaves pretty much like a Normal distribution with mean np and standard deviation , so around 60% of the data are in the interval [mean -s, mean +s] and 40% outside, so roughly <em>20% of the data should be in [0, mean-s] </em>
Answer:
The number of reserved seat is 120 and number of general seat is 640.
Step-by-step explanation:
Given,
Total number of seats = 760
Total collected Money = $3280
Solution,
Let the total number of reserved seat be x.
And the total number of general seat be y
Hence total number of seats is the sum of total number of reserved seat and the total number of general seats.
So the equation can be written as;
Again, total money collected is the sum of fees of one reserved seat times total number of reserved seat and fees of one general seat times the total number of general seats.
So the equation can be written as;
Now, multiplying equation 1 by 4 and then subtract it from equation 2.
On substituting the value of x in equation 1, we get;
Thus the number of reserved seat is 120 and number of general seat is 640.