Question

Two containers, A and b begin with equal volumes of liquid. 120 mL is then poured from a to B. Container b now contains four times as much liquid as A. Find the volume of liquid left in container a at the end

Answer 1

If n is used as the initial amount of liquid in both A and B:

4(n-120) = n+120
4n-480 = n+120
3n = 600
n = 200

Each container originally held 200ml. Container A now has 80ml and Container B has 320ml

Answer 2

Answer:

Step-by-step explanation:

Alright, lets get started.

Suppose A and B , both has initial volume, say x

120 ML is poured from B to A, then new volumes of A and B will be:

new volume of A $= (x-120)$

new volume of B $= (x+120)$

Volume of B is now four times volume of A, then

$(x+120) = 4 (x-120)$

$(x+120) = 4x-480$

$3x = 600$

$x = 200$

So, the initial volume of A and B containers is 200

So, at the end, volume of container A = $200-120= 80$

Hence the answer is 80   :    Answer

Hope it will help :)