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Eduardwww [97]
4 years ago
6

What are Strengths and weaknesses in the sociological imagination

Advanced Placement (AP)
1 answer:
lidiya [134]4 years ago
7 0
The strength of the it is that it reminds all theorists that they are also are a product of what they study and that they should also never forget that. There is never a final objectifying.

whereas, the disadvantage of it is it seems inevitable almost that engaging in such a deep and complex study will have an different effect on the sociologist’s ability to work with the everyday world in a free and uncomplicated manner.
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how did contractionist account for identical fossils being on the continents of south america and africa
vfiekz [6]
They didn't account for it they said animals and dinosaurs was there when the meteor crashed into the earth
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3 years ago
"Going to Cedar Point, fields of soy beans all around, in the seat of the car, Joyce riding, and Sue, together." This constructi
Nutka1998 [239]
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4 years ago
Read 2 more answers
Solve the following systems of 3-variable linear equations.​
Zina [86]

Answer:

x = 9/25, y = 7/25, z = 4/25

Explanation:

step 1: solve for y in first equation to use substitution

y = -2x + 1

step 2: insert into second equation to eliminate y variable and work with two variables

3(-2x+1) + z = 1 (now distribute)

-6x + 3 + z = 1 (bring over the -3)

-6x + z = -2

step 3: now left with -6x + z = -2 and x + 4z = 1, so eliminate z

-6x + z = -2 (multiply by 4)

4(-6x + z = -2)

-24x + 4z = -8

-

x + 4z = 1 (brought down third equation)

-25x = -9

x = 9/25

then just plug in x into the third equation to solve for z, followed by plugging it into the first equation to solve for y. you should end with y = 7/25 and z = 4/25

6 0
3 years ago
Which of the following is the same as (V3+V2)2 ?
Drupady [299]
Solution. To check whether the vectors are linearly independent, we must answer the following question: if a linear combination of the vectors is the zero vector, is it necessarily true that all the coefficients are zeros?
Suppose that
x 1 ⃗v 1 + x 2 ⃗v 2 + x 3 ( ⃗v 1 + ⃗v 2 + ⃗v 3 ) = ⃗0
(a linear combination of the vectors is the zero vector). Is it necessarily true that x1 =x2 =x3 =0?
We have
x1⃗v1 + x2⃗v2 + x3(⃗v1 + ⃗v2 + ⃗v3) = x1⃗v1 + x2⃗v2 + x3⃗v1 + x3⃗v2 + x3⃗v3
=(x1 + x3)⃗v1 + (x2 + x3)⃗v2 + x3⃗v3 = ⃗0.
Since ⃗v1, ⃗v2, and ⃗v3 are linearly independent, we must have the coeffi-
cients of the linear combination equal to 0, that is, we must have
x1 + x3 = 0 x2 + x3 = 0 ,
x3 = 0
from which it follows that we must have x1 = x2 = x3 = 0. Hence the
vectors ⃗v1, ⃗v2, and ⃗v1 + ⃗v2 + ⃗v3 are linearly independent.
Answer. The vectors ⃗v1, ⃗v2, and ⃗v1 + ⃗v2 + ⃗v3 are linearly independent.
4 0
3 years ago
It can be inferred that the author's primary purpose in this passage is to
stellarik [79]

Answer:

It's C.

Explanation:

Took the test on Edge.

7 0
3 years ago
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