Answer:
Distance= 6.6 miles
Bearing= N 62.854°W
Step-by-step explanation:
Let's determine angle b first
Angle b=20° (alternate angles)
Using cosine rule
Let the distance between the liner and the port be x
X² =8.8²+2.4²-2(8.8)(2.4)cos20
X²= 77.44 + 5.76-(39.69)
X²= 43.51
X= √43.51
X= 6.596
X= 6.6 miles
Let's determine the angles within the triangle using sine rule
2.4/sin b = 6.6/sin20
(2.4*sin20)/6.6= sin b
0.1244 = sin b
7.146= b°
Angle c= 180-20-7.146
Angle c= 152.854°
For the bearing
110+7.146= 117.146
180-117.146= 62.854°
Bearing= N 62.854°W
Answer:
302.33
Step-by-step explanation:
Answer:
2x^2 + 3x – 54 = (2x - 9) (x + 6), so A and F
Step-by-step explanation:
Answer: 13,000
Step-by-step explanation:
I = prt
I = (.65)($4000)(5)
I = 2600(5)
I = 13,000
Answer:
the top one, (-1,3)
Step-by-step explanation:
