Answer:
The 95% confidence interval for the population proportion is (0.1456, 0.2344). This means that we are 95% sure that the true proportion of employed American who say that they would fire their boss if they could is between 0.1456 and 0.2344.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 95% confidence interval for the population proportion is (0.1456, 0.2344). This means that we are 95% sure that the true proportion of employed American who say that they would fire their boss if they could is between 0.1456 and 0.2344.
Tenth have to make answer longer for this app sorry
1. Take away the parentheses. x+2x+40+3x-50=15002
2. Add the X’s together.
x+2x+3x= 6x —> 6x+40-50=15002
3. Subtract 50 from 40.
40-50= -10 —> 6x-10=15002
4. Move -10 to the right hand side to make it positive.
6x=15002+10
5. Add 15002 and 10 together.
6x=15012
6. Divide 15012 by 6. Which makes the answer X=2502
3 x + 2y=8= 0 thats the answer bro