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anastassius [24]
4 years ago
9

The population of osaka japan declined at an average annual rate of 0.05% for five years between 1995 and 2000. If the populatio

n of osaka was 11,013,000 in 2000 and it continues to decline at the same rate, predict the population in 2050
Mathematics
1 answer:
fgiga [73]4 years ago
8 0

Answer:

10,741,021\ people

Step-by-step explanation:

we know that

The equation of a exponential decay function can be written as

y=a(1-r)^x

where

y ---> is the population of Osaka japan

x ---> the number of years since 2000

a ---> is the initial value or y-intercept

r is the rate of change

we have

a=11,013,000\ people

r=0.05\%=0.05/100=0.0005

substitute

y=11,013,000(1-0.0005)^x

y=11,013,000(0.9995)^x

Predict the population in 2050

so

2050-2000=50\ years

For x=50 years

substitute in the equation

y=11,013,000(0.9995)^{50}

y=10,741,021\ people

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Solution:

As per the problem

A person is born every 5 seconds and a person dies every 12 seconds.

Here the LCD of 5 and 12 is 60.

The number of person born in 60 seconds=\frac{60}{5}=12\\

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Hence Population increase in 60 seconds is=12-5=7\\

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3 years ago
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Answer:

y = -34x + 62

Step-by-step explanation:

<u>Use the point slope form:  (y - y1) = m(x - x1)</u>

<u />

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y + 6 - 6 = -34x + 68 - 6

y = -34x + 62

Answer:  y = -34x + 62

4 0
3 years ago
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Which of the following p values will lead us to reject the null hypothesis if the level of significance equals .05?
V125BC [204]

Answer:

So then our significance level is \alpha=0.05 and we need to remember these two conditions:

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2) If the p value p_v \geq \alpha we have enough evidence to FAIL reject the null hypothesis at the significance level given

And baed on the options we see that the only possibility would be:

d. 0.015

Step-by-step explanation:

We want to know for which value we would REJECT the null hypothesis.

So then our significance level is \alpha=0.05 and we need to remember these two conditions:

1) If the p value p_v we have enough evidence to reject the null hypothesis at the significance level given

2) If the p value p_v \geq \alpha we have enough evidence to FAIL reject the null hypothesis at the significance level given

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Nesterboy [21]

Answer:

<h2><em><u>62</u></em><em><u>.</u></em><em><u>2</u></em></h2>

Step-by-step explanation:

4n × 2 + 43

<em>[</em><em>By</em><em> </em><em>putting</em><em> </em><em>the</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>n</em><em> </em><em>=</em><em> </em><em>2</em><em>.</em><em>4</em><em>]</em>

= (4 ×2.4) × 2 + 43

= 9.6 × 2 + 43

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4 0
3 years ago
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QUICK HOW DO YOU SIMPLIFY THIS EQUATION
Yanka [14]
20.25-9(1/2)+11
=20.25-4.5+11
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3 years ago
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