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anastassius [24]
4 years ago
9

The population of osaka japan declined at an average annual rate of 0.05% for five years between 1995 and 2000. If the populatio

n of osaka was 11,013,000 in 2000 and it continues to decline at the same rate, predict the population in 2050
Mathematics
1 answer:
fgiga [73]4 years ago
8 0

Answer:

10,741,021\ people

Step-by-step explanation:

we know that

The equation of a exponential decay function can be written as

y=a(1-r)^x

where

y ---> is the population of Osaka japan

x ---> the number of years since 2000

a ---> is the initial value or y-intercept

r is the rate of change

we have

a=11,013,000\ people

r=0.05\%=0.05/100=0.0005

substitute

y=11,013,000(1-0.0005)^x

y=11,013,000(0.9995)^x

Predict the population in 2050

so

2050-2000=50\ years

For x=50 years

substitute in the equation

y=11,013,000(0.9995)^{50}

y=10,741,021\ people

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Answer:

Step-by-step explanation:

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3 years ago
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leonid [27]
We have that

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case 2) </span>3x 5 + 3x 4 + x 3--------> <span>A. Quintic trinomial
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<span>
case 3) </span>x 2 + 3----------> <span>B. quadratic binomial
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6 0
3 years ago
Let f(x)=−1/4(x+4)^2−8 . What is the average rate of change for the quadratic function from x=−2 to x = 2? Enter your answer in
kiruha [24]

Answer:

Average rate of change of function is -2.

Step-by-step explanation:

Given f(x)=\frac{-1}{4}(x+4)^2-8.

we have to find the average rate of change for the quadratic function from x=−2 to x = 2.

f(-2)=\frac{-1}{4}(-2+4)^2-8=\frac{-1}{4}(4)-8=-9

f(2)=\frac{-1}{4}(2+4)^2-8=\frac{-1}{4}(36)-8=-17

The average rate of change of the function  f(x) on interval [-2,2] is

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3 0
4 years ago
Use the diagram to determine which statement is true
hichkok12 [17]
A. Area of ABCD - Area of DGA = Area of DEFG
s^2 - 1/2bh = s^2
(5)^2 - 1/2(4)(3) = (3)^2
25 - 1/2(12) = 9
25 - 24 = 9
1 not equal to 9

B. Area of ABCD - Area of GHIA = Area of DGA
s^2 - s^2 = 1/2bh
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The answer is D.
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3 years ago
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aleksandrvk [35]
B. D. Are equal to 300
7 0
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