2(9t + 2) + 9 + 9 =
= 18t + 18 + 9 + 9 = <u>1</u><u>8</u><u>t</u><u> </u><u>+</u><u> </u><u>3</u><u>6</u> ← the end
3 buses to 11 cars is the ratio
Given that R=130 and S=90. ST are congruent to UT so therefore U=90 and T=50
There are 6 numbers on each die.
The total number of out comes is 6 x 6 = 36.
To get a sum of 4, the combinations are: 1 & 3, 2 & 2 or 3 & 1.
To get a sum of 8, the combinations are: 1 & 7, 2 & 6, 3 & 5, 4 & 4, 7 & 1, 6 & 2, 5 & 3
The total of those combinations are: 3 + 7 = 10 total combinations of a sum of either 4 or 8.
The probability of either is 10/36, which can be reduced to 5/18.