Numbers are x and y
x is 5 more than y
x=5+y
product is -3
xy=-3
solve
sub 5+y for x since x=5+y
(5+y)y=-3
5y+y^2=-3
add 3 to both sides
y^2+5y+3=0
use quadratic formula where
ay^2+by+c=0
y=
a=1
b=5
c=3
y=
y=
y=
y=
or
the second number is 5 more or 10/2 more
add 10/2 to each
x=
or
the numbers are
and
or
and
aprox
the numbers are
-0.697224 and 5.967224 or
-4.302775 and 0.697224
Answer:
<u>Using below system of inequalities</u>
<u>Following the rules </u>
- 1. Finding x- and y - intercepts
- 2. Connecting with dotted line for each as no equal symbol present in any inequality
- 3. Shade respective regions
- 4. Solution is the intersection of the shades regions
- 5. Select any three points in the solution region
<u>Line 1</u>
- y > 2x - 3
- x- intercept: y = 0 ⇒ 0 = 2x - 3 ⇒ 2x = 3 ⇒ x = 1.5
- y - intercept: x = 0 ⇒ y = -3
- Shaded region is above the line (or to the left)
<u>Line 2</u>
- y < x + 1
- x- intercept: y = 0 ⇒ 0 = x + 1 ⇒ x = -1
- y - intercept: x = 0 ⇒ y = 1
- Shaded region is below the line (or to the right)
<u>Selected points are:</u>
Answer:
4
Step-by-step explanation:
Because it's degree is 4
Let x = the number of marbles for Phil
Then 3x = the number of marbles for Peter
Together they have 3x+x=48 or 4x=48 and x=12
So Phil has x = 12 marbles and Peter has 3x, let x = 12, 3(12) = 36 marbles.
Peter has 24 more marbles than Phil.