Answer:
(0,3) is the solution set for given system.
Step-by-step explanation:
Given that:
3x+4y=12 ------- eq1
2x-3y= -9 ------- eq2
Multiplying eq1 with 2 and eq2 with 3 we get:
6x + 8y = 24 --------- eq1
6x - 9y = -27 -------- eq2
Subtracting eq2 from 1 we get:
17y = 51
Dividing both sides by 17 we get:
y = 3
Putting value of 3 in eq1 we get:
3x + 4(3) = 12
3x + 12 = 12
3x = 0
Dividing both sides by 3
x = 0
So the solution set will be: (0,3)
i hope it will help you.
2(x + 3) = x - 4
distribute
2x + 6 = x - 4
either subtract 6 from both sides or add 4. i will be subtracting 6.
2x = x - 10
subtract x from both sides
x = -10
Yes it is 1/8.You don’t multiply the top part of the fraction,just the bottom.
X-intercept. y-intercept
4*0-2x=16. 4y-2*0=16
-2x+0=16. 4y-0=16
-0. -0. +0 +0
-2x. /-2 = 16/-2 4y/4 =16/4
x = -8. y = 4
(-8,0) (0,4)
