Answer:
<em>The correct answer is First option</em>:
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Step-by-step explanation:
We are given 4 equations:
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Let us solve the first two:

Multiplying (2) with 10 and adding to (1):

So, approximately, value of x is -0.3.
Putting value of x in (2):

value of x is approximately -0.3 so y is approximately 1.4.
So, the solution is
(–0.3, 1.4)
<em>The correct answer is First option</em>:

The above two equations have a solution <em>approximately (–0.3, 1.4).</em>