The answer is 4. You do 12 times 1/3. This is because this is important in order to find out the answer. The answer is 4.
Answer:
1 : 8
Step-by-step explanation:
For similar figures with ratio of sides = a : b
Then ratio of areas = a² : b² and
ratio of volumes = a³ : b³
Given ratio of areas = 1 : 4
linear ratio = 
: 
= 1 : 2
ratio of volumes = 1³ : 2³ = 1 : 8
Create a system if equations to solve this.
First equation:
25m + 24e = 220
Second equation:
m + e = 9
Then you must solve the second equation for a variable.
Change m + e = 9 to e = 9 - m.
Then substitute (9 - m) for e in the first equation.
So 25m +24e = 220 becomes 25m + 24(9 - m) = 220.
Now you can solve the first equation because the only variable in it is m.
25m + 24(9 - m) = 220 (Original equation)
25m + 216 - 24m = 220 (Distribute)
m + 216 = 220 (Combine like terms)
m = 4 (Simplify)
Now plug in 4 for m in the second equation.
m + e = 9 (Original equation)
(4) + e = 9 (Substitute)
e = 5 (Simplify)
m represents Math Books and e represents English Books, so Nicole purchased 4 Math Books and 5 English Books.
Answer: The rate of change is 11.6666...
Step-by-step explanation:
You subtract 95 by 60 and you get 35.
You divide it by 3 because it happened over 3 weeks.
After dividing your answer is 11.6666...
Answer:
e. The probability of observing a sample mean of 5.11 or less, or of 5.29 or more, is 0.018 if the true mean is 5.2.
Step-by-step explanation:
We have a two-tailed one sample t-test.
The null hypothesis claims that the pH is not significantly different from 5.2.
The alternative hypothesis is that the mean pH is significantly different from 5.2.
The sample mean pH is 5.11, with a sample size of n=50.
The P-value of the test is 0.018.
This P-value corresponds to the probability of observing a sample mean of 5.11 or less, given that the population is defined by the null hypothesis (mean=5.2).
As this test is two-tailed, it also includes the probability of the other tail. That is the probability of observing a sample with mean 5.29 or more (0.09 or more from the population mean).
Then, we can say that, if the true mean is 5.2, there is a probability P=0.018 of observing a sample of size n=50 with a sample mean with a difference bigger than 0.09 from the population mean of the null hypothesis (5.11 or less or 5.29 or more).
The right answer is e.
