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leva [86]
3 years ago
14

Please help me!

Mathematics
1 answer:
vampirchik [111]3 years ago
7 0

Answer:

the answer is

y=(x+1)2+4

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Hello there!
otez555 [7]

Answer:

24  Domain: s>=2  or s<=-2

25. 3x^2 +14x +10

26. x^2 -2x+5  

Step-by-step explanation:

24.  Domain is the input or s values

square roots must be greater than or equal to zero

s^2-4 >=0

Add 4 to each side

s^2 >=4

Take the square root

s>=2  or s<=-2


25.  f(g(x))  stick g(x) into f(u) every place you see a u

f(u) = 3u^2 +2u-6

g(x) = x+2

f(g(x) = 3(x+2)^2 +2(x+2) -6

Foil the squared term

       = 3(x^2 +4x+4) +2x+4-6

Distribute

       = 3x^2 +12x+12 +2x+4-6

Combine like terms

   =3x^2 +14x +10


26 f(g(x))  stick g(x) into f(u) every place you see a u

f(u) = u^2+4

g(x) = x-1

f(g(x) = (x-1)^2 +4

Foil the squared term

         = (x^2 -2x+1) +4

         = x^2 -2x+5  

7 0
3 years ago
2x + 10<br> 600<br> Vocabulary:<br> Equation:<br> Solve for :
aleksandr82 [10.1K]
The answer would be 295
3 0
3 years ago
Read 2 more answers
4.<br> The probability of it raining tomorrow is 0.34. What is the probability it doesn't<br> rain?
ELEN [110]

Answer:

99.66%

Step-by-step explanation:

4 0
2 years ago
Find the absolute minimum and absolute maximum values of f on the given interval. f(x) = ln(x2 + 3x + 4), [−2, 2]
vivado [14]
The vertex (minimum) of the quadratic ax² +bx +c is located at x=-b/(2a). This means the minimum value of f(x) will be found at x = -3/(2*1) = -1.5.

Since the vertex of the quadratic is less than 0, the maximum value of the quadratic will be found at x=2, the end of the interval farthest from the vertex.

On the given interval, ...
  the absolute minimum value of f is f(-1.5) = ln(1.75) ≈ 0.559616
  the absolute maximum value of f is f(2) = ln(14) ≈ 2.639057

4 0
3 years ago
Is 419.10 less or greater than 419.099
Alex Ar [27]
They are equal its just rounded up to one decimal place

4 0
3 years ago
Read 2 more answers
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