Please answer quickly with explanation

In 2004, Cindy had $4000 in a mutual fund account. In 2005, the

gtnhenbr [62]

6,250
1,000/4,000 = 25/100
25/100 = x/5,000
x = 1,250

5,000 + 1,250 = 6,250

4 0

2 years ago

The presence of a midpoint will result in what type of segments?

maks197457 [2]

Answer:

congruent segments

Step-by-step explanation:

Congruent segments. Take a line, cut it in half, superipose one half over the other half; you'll have congruence.

5 0

2 years ago

Read 2 more answers

I need help with this problem ASAP!

Karo-lina-s [1.5K]

Form a right angle triangle joining both given points to the origin, we get:

Perpendicular = 2 ( distance is always positive)

Base = 4 ( same logic)

Applying Pythagorus theorem

Hypotenuse = root of ( perpendicular squared + base squared)

Hypotenuse = root of 20 = 2 * root 5

Using x instead of theta

Sin x = perpendicular/hypotenuse

Cos x = base/hypotenuse

Sin x = -1/ root 5

Cos x = -2/ root 5

High probability of this answer being wrong.

Double check recommended.

4 0

2 years ago

Calvin is making breakfast for his family. The pancake recipe requires 12 tablespoons of butter and 6 eggs. The ricipe makes 24

Crazy boy [7]

The ratio is
$\frac{6\ eggs}{24\ pancakes}$
which simplifies to
$\frac{1}{4}$
or 1:4

3 0

2 years ago

In a beach town, 13% of the residents own boats. A random sample of 100 residents was selected. What is the probability that les

mariarad [96]

Answer:

Approximately $0.038$ (or equivalently $3.8\%$ ,) assuming that whether each resident owns boats is independent from one another.

Step-by-step explanation:

Assume that whether each resident of this town owns boats is independent from one another. It would be possible to model whether each of the $n = 100$ selected residents owns boats as a Bernoulli random variable: for $k = \lbrace 1,\, \dots,\, 100\rbrace$ , $X_k \sim \text{Bernoulli}(\underbrace{0.13}_{p})$ .

$X_k = 0$ means that the $k$ th resident in this sample does not own boats. On the other hand, $X_k = 1$ means that this resident owns boats. Therefore, the sum $(X_1 + \cdots + X_{100})$ would represent the number of residents in this sample that own boats.

Each of these $100$ random variables are all independent from one another. The mean of each $X_k$ would be $\mu = 0.13$ , whereas the variance of each $X_k\!$ would be $\sigma = p\, (1 - p) = 0.13 \times (1 - 0.13) = 0.1131$ .

The sample size of $100$ is a rather large number. Besides, all these samples share the same probability distribution. Apply the Central Limit Theorem. By this theorem, the sum $(X_1 + \cdots + X_{100})$ would approximately follow a normal distribution with:

mean $n\, \mu = 100 \times 0.13 = 13$ , and
variance $\sigma\, \sqrt{n} = p\, (1 - p)\, \sqrt{n} = 0.1131 \times 10 = 1.131$ .

$11\%$ of that sample of $100$ residents would correspond to $11\% \times 100 = 11$ residents. Calculate the $z$ -score corresponding to a sum of $11$ :

$\begin{aligned}z &= \frac{11 - 13}{1.131} \approx -1.77 \end{aligned}$ .

The question is (equivalently) asking for $P( (X_1 + \cdots + X_{100}) < 11)$ . That is equal to $P(Z < -1.77)$ . However, some $z$ -tables list only probabilities like $P(Z > z)$ . Hence, convert $P(Z < -1.77)\!$ to that form: