All categories

3 years ago

Find the product: 377(10, 000).

Mathematics

1 answer:

Illusion [34]3 years ago

7 0

Answer:

37, 700, 000

Step-by-step explanation:

377(10,000) = 377 x 10,000

= 37, 700, 000

an easy way to see it is to just add the number of zeros from 10,000 to 377. since there are four zeros, you put four zeros behind 377.

[it's not mathematical but it helps u see the answer better. and it only works with numbers that start with 1]

You might be interested in

The football team has a total of 50 jerseys. There are 5 medium-sized jerseys. What percent of the jerseys are medium-sized jer

laila [671]

The answer would be 10%

4 0

3 years ago

Read 2 more answers

The international cricket team is going to stadium to play the T20 cricket game. A coordinate grid is superimposed on a highway

marysya [2.9K]

Answer:

The coordinate of the rest stop is: $(5,2.5)$

The distance between the hotel and the stadium is 32 miles

Step-by-step explanation:

Given

$(x_1,y_1) = (3,4)$ --- Team hotel

$(x_2,y_2) = (7,1)$ --- Stadium

Solving (a): The coordinates of the rest stop

The rest stop is at half way;

So, the coordinate is:

$(x,y) = \frac{1}{2}(x_1+x_2,y_1+y_2)$

This gives:

$(x,y) = \frac{1}{2}(3+7,4+1)$

$(x,y) = \frac{1}{2}(10,5)$

Open bracket

$(x,y) = (5,2.5)$

Solving (b): Distance between the hotel and the stadium

We have:

$(x_1,y_1) = (3,4)$ --- Team hotel

$(x_2,y_2) = (7,1)$ --- Stadium

The distance (d) is:

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

So, we have:

$d = \sqrt{(3 - 7)^2 + (4 - 1)^2}$

$d = \sqrt{(-4)^2 + 3^2}$

$d = \sqrt{16 + 9}$

$d = \sqrt{25}$

$d =5$

From the question, we have:

$1\ unit = 6.4\ miles$

So:

$d =5 * 6.4\ miles$

$d =32\ miles$

3 0

2 years ago

Question Express the inequality x > -1 using interval notation

Nimfa-mama [501]

Step-by-step explanation:

x > -1

x = {0,1,2,...}

$\lang -1,+\infty \rang$

4 0

2 years ago

WILL GIVE BRAINLIEST! SUPER CONFUSED!!!

kondor19780726 [428]

Answer:

For 1948 Men's :Interquartile range is 1.5, Median is 58.3

For 2012 Men's: Interquartile range is 0.315, Median is 47.86

You can infer that in 2012 the swimmers were better and it was more competitive as the interquartile range was lower and the median was also lower as well

Step-by-step explanation:

1948 Men's 100m

57.3, 57.8, 58.1, 58.3, 58.3, 59.3, 59.6,1:00.5

⬆ ⬆ ⬆

Low IQR Median High IQR

Low IQR is average of 57.8 and 58.1 = 57.95

High IQR is average of 59.3 and 59.6 = 59.45

Median is average of 58.3 and 58.3 = 58.3

Interquartile range is High IQR- Low IQR

59.45 - 57.95=1.5

2012 Men's 100m

47.52, 47.53, 47.8, 47.84, 47.88, 47.92, 48.04, 48.44

⬆ ⬆ ⬆

Low IQR Median High IQR

Low IQR is average of 47.53 and 47.8 = 47.665

High IQR is average of 48.04 and 47.92 = 47.98

Median is average of 47.88 and 47.84 = 47.86

Interquartile range is High IQR-Low IQR

47.98-47.665=0.315

5 0

3 years ago

Find the inverse function of y=x^5+9

ollegr [7]

Answer:

$\sqrt[5]{x - 9}$

Step-by-step explanation:

y=x^5+9

To find inverse function make x the subject, first:

y=x^5+9

y - 9 = x^5

x = $\sqrt[5]{y - 9}$

$y^{-1} = \sqrt[5]{x - 9}$

so inverse function of y=x^5+9 is $\sqrt[5]{x - 9}$

3 0

2 years ago

Read 2 more answers