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mote1985 [20]
3 years ago
5

99 POINTS PLS HELP Write the equation in slope-intercept form. 4x + 3y = 15

Mathematics
2 answers:
Kisachek [45]3 years ago
8 0

To write in slope intercept form solve the equation for y:

4x + 3y =15

Subtract 4x from both sides:

3y = -4x +15

Now get Y by itself by divide all terms by 3:

y = -4/3x + 5

Aleks04 [339]3 years ago
3 0

Answer:

It's the  second choice:

y = (-4/3)x + 5

Step-by-step explanation:

Slope-intercept form is y = mx + c where m = the slope and c the y-intercept.

4x + 3y = 15

3y = -4x + 15

Divide through by 3:

y = (-4/3)x + 5.

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A=?<br><br> b=?<br><br> C =?<br><br> Can someone tell me the answer please
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Answer:

Below.

Step-by-step explanation:

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Use the given function and the given interval to complete parts a and b. f (x )f(x)equals=negative 2 x cubed plus 21 x squared m
Leya [2.2K]

Answer:

(A)The absolute maximum of f(x) is at x=5

Step-by-step explanation:

F(x)=−2x³+21x²−60x on [1,6]

Find the first derivative.

f'(x)=-6x²+42x-60

Set the first derivative equal to zero.

-6x²+42x-60=0

Solve to find the critical points.

x=2,5

Next, we use the endpoints and all critical points on the interval to test for any absolute extrema over the given interval.

x=1,2,5,6

This is done by evaluating the function at x=1,2,5,6.

F(1)=−2(1)³+21(1)²−60(1)=-41

F(2)=−2(2)³+21(2)²−60(2)=-52

F(5)=−2(5)³+21(5)²−60(5)=-25

F(6)=−2(6)³+21(6)²−60(6)=-36

The maximum will occur at the highest f(x) value and the minimum will occur at the lowest f(x) value.

Absolute Maximum: (5,-25)

Absolute Minimum: (2,-52)

The graph is attached.

The absolute minimum and maximum of f(x) are (2,-52) and (5,-25) respectively.

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