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3 years ago

5

Bertha and vernon both scuba dive. Berthas dive was -100 feet her dive was 5 times deeper than vernons dive. What depth did vern

ons dive reach

1 answer:

yulyashka [42]3 years ago

6 0

Answer:

20

Step-by-step explanation:

Berthas dive is 5 times deeper than vernons dive and bertha dived 100ft so

100/5

=20

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Please help. I’ll mark you as brainliest if correct!

balu736 [363]

Answer: x= -1, z=2, y= -4

Step-by-step explanation:

System of equations:

-5x - 4y - 3z= 15 +

<u>-10x + 4y + 6z= 6</u>

-15x + 3z = 21 ------> 3 (-5x + z) = 7.3

-5x + z = 7

now,

-10x + 4y + 6z= 6

2(-5x + z) + 4y + 4z = 6

14 + 4y + 4z = 6

7 + 2y + 2z = 3

2y + 2z= -4

y+z=-2

Now we were using the equation: 20x + 4y + 4z = -28

20x + 4(y+z) = 20x -8= - 28

20 x = -20

x= -1

With this we can find y and z

X=-1

-5x + z = 7

z= 2

y+z=-2

y=-4

Finally we have: x= -1, z=2, y= -4

I hope this can help you.

Thank you

3 0

2 years ago

Consider a binomial experiment with 15 trials and probability 0.35 of success on a single trial.

DedPeter [7]

Answer:

a

$P(X = 10 ) = 0.0096$

b

$P(X = 10 ) = 0.0085$

c

Option A is correct

Step-by-step explanation:

From the question we are told that

The sample size is n = 15

The probability of success is $p = 0.35$

The number of success we are considering is r = 10

Now the probability of failure is mathematically evaluated as

$q = 1- p$

substituting value

$q = 1- 0.35$

$q = 0.65$

Now using the binomial distribution to find the probability of exactly 10 successes we have that

$P(X = r ) = [\left n } \atop {r}} \right. ] * p^r * q^{n- r}$

substituting values

$P(X = 10 ) = [\left 15 } \atop {10}} \right. ] * p^{10}* q^{15- 10}$

Where $[\left 15 } \atop {10}} \right. ]$ mean 15 combination 10 which is evaluated with a calculator to obtain

$[\left 15 } \atop {10}} \right. ] = 3003$

So

$P(X = 10 ) = 3003 * 0.35 ^{10}* 0.65^{15- 10}$

$P(X = 10 ) = 0.0096$

Now using the normal distribution to approximate the probability of exactly 10 successes, we have that

$P(X = r ) = P( r < X < r )$

Applying continuity correction

$P(X = r ) = P( r -0.5 < X < r +0.5)$

substituting values

$P(X = 10) = P( 10-0.5 < X < 10+0.5)$

$P(X = 10 ) = P( 9.5 < X < 10.5)$

Standardizing

$P(X = r ) = P( \frac{9.5 - \mu }{\sigma } < \frac{X - \mu }{\sigma } < \frac{10.5 - \mu}{\sigma } )$

The where $\mu$ is the mean which is mathematically represented as

$\mu = n * p$

substituting values

$\mu = 15 * 0.35$

$\mu = 5.25$

The standard deviation is evaluated as

$\sigma = \sqrt{n * p * q }$

substituting values

$\sigma = \sqrt{15 * 0.35 * 0.65 }$

$\sigma = 1.8473$

Thus

$P(X = 10 ) = P( \frac{9.5 - 5.25 }{1.8473 } < \frac{X - 5.25 }{1.8473 } < \frac{10.5 - 5.25}{1.8473 } )$

$P(X = 10 ) = P( 2.30 < Z < 2.842 )$

$P(X = 10 ) = P(Z < 2.842 ) - P(Z < 2.30 )$

From the normal distribution table we obtain the $P(Z < 2.841)$ as

$P(Z < 2.841) = 0.99775$

And the $P(Z < 2.30)$

$P(Z < 2.30) = 0.98928$

There value can also be obtained from a probability of z calculator at (Calculator dot net website)

So

$P(X = 10) = 0.99775 - 0.98928$

$P(X = 10 ) = 0.0085$

Looking at the calculated values for question a and b we see that the values are fairly different.

8 0

3 years ago

Baker sammy helppppp

svetoff [14.1K]

Answer:

$a = 8.5t$

$y = 32.55$

Step-by-step explanation:

Solving (9): The equation of the table

We start by calculating the slope (m)

$m = \frac{a_2 - a_1}{t_2 - t_1}$

Where:

$(t_1,a_1) = (15,127.5)$

$(t_2,a_2) = (16.5,140.25)$

$m = \frac{140.25 - 127.5}{16.5 - 15}$

$m = \frac{12.75}{1.5}$

$m = 8.5$

The equation is then calculated using:

$a = m(t - t_2) + a_2$

So, we have:

$a = 8.5(t - 16.5) + 140.25$

Open bracket

$a = 8.5t - 140.25 + 140.25$

$a = 8.5t$

Solving (10):

$4.8y = 156.24$

Required

Find x

Divide both sides by 4.8

$y = 32.55$

7 0

2 years ago

4. If A = 45° and B = 30°, verify the following<br> (a) sin (A - B) = sinA.cosB - COSA, sinB.

noname [10]

Uhh enuhlish okkk hehehehe

7 0

2 years ago

What is a parabola? pls help because i need this quick.

KiRa [710]

A parabola is a curved shape in a graph that has either a maximum or a minimum (which is the fixed point) and any point is equidistant from that fixed point. You can tell it is a parabola because most likely in an equation the x with be squared.

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3 years ago