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4 years ago

If the rectangle below has an area of 32 sq. units, what is the area of the triangle?

Mathematics

2 answers:

vesna_86 [32]4 years ago

8 0

Answer:

B. 16 sq. units

Step-by-step explanation:

If you divide the rectangle, you will get 2 triangles. Therefore you will divide your answer from the rectangle by two.

Rama09 [41]4 years ago

5 0

Step-by-step explanation:

here, on this as the measure of triangle is alredy given separately we don'tneed its area. We just can use formula of area of triangle and simpfy it to get answer.

the measures of perpendicular (p)= 8

and base (b)=4

now, area of triangle (a)=1/2×b×p

or, a = 1/2 ×4×8

by simplifying it we get 16 sq.units.

hope it helps...

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Find the value of x.

kiruha [24]

X=5
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3 years ago

Read 2 more answers

If Tanisha has $1000 to invest at 7% per annum compounded semiannually, how long will it be before she has $1600? If the co

Sphinxa [80]

Answer:

Using continuous interest 6.83 years before she has $1600.

Using continuous compounding, 6.71 years.

Step-by-step explanation:

Compound interest:

The compound interest formula is given by:

$A(t) = P(1 + \frac{r}{n})^{nt}$

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per unit year and t is the time in years for which the money is invested or borrowed.

Continuous compounding:

The amount of money earned after t years in continuous interest is given by:

$P(t) = P(0)e^{rt}$

In which P(0) is the initial investment and r is the interest rate, as a decimal.

If Tanisha has $1000 to invest at 7% per annum compounded semiannually, how long will it be before she has $1600?

We have to find t for which $A(t) = 1600$ when $P = 1000, r = 0.07, n = 2$

$A(t) = P(1 + \frac{r}{n})^{nt}$

$1600 = 1000(1 + \frac{0.07}{2})^{2t}$

$(1.035)^{2t} = \frac{1600}{1000}$

$(1.035)^{2t} = 1.6$

$\log{1.035)^{2t}} = \log{1.6}$

$2t\log{1.035} = \log{1.6}$

$t = \frac{\log{1.6}}{2\log{1.035}}$

$t = 6.83$

Using continuous interest 6.83 years before she has $1600

If the compounding is continuous, how long will it be?

We have that $P(0) = 1000, r = 0.07$

Then

$P(t) = P(0)e^{rt}$

$1600 = 1000e^{0.07t}$

$e^{0.07t} = 1.6$

$\ln{e^{0.07t}} = \ln{1.6}$

$0.07t = \ln{1.6}$

$t = \frac{\ln{1.6}}{0.07}$

$t = 6.71$

Using continuous compounding, 6.71 years.

7 0

3 years ago

THINKING

Tanzania [10]

Answer:

k = 2

Step-by-step explanation:

Given the equations:

g(x) = 3x² + 8x + k

f(x) = 2x - 1

At the intersection point:

g(x) = f(x)

3x² + 8x + k = 2x - 1

3x² + 6x + (k+1) = 0

If there is only one intersection point, the discriminant must be equal to zero:

b² - 4(a)(c) = 0

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36 - 12k - 12 = 0

24 = 12k

24/12 = k

2 = k

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3 years ago

Solve for y in terms of x. (Isolate y) x-y=6

meriva

Y = x - 6

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3 years ago

3x < 18 A) x < 6 B) x > 6 Eliminate C) x < 15 D) x > 54

Flura [38]

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3 years ago