Answer:
![\left[\begin{array}{ccc}0&3&4\\0&7&-1\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%263%264%5C%5C0%267%26-1%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Answer:
196/45 or 4 16/45 | They probably want a fraction but: 4.355555555(6)
Answer: 9" by 7"
Step-by-step explanation:
let the dimensions of the rectangle be x and y
equation 1: xy=63
equation 2: 2(x+y)=32
first, rearrange the terms
(1′): y=63/x
(2′): y=16−x
(1′)-(2′): 0=63/x−16+x
multiply the equation by x
0=x2−16x+63
0=(x−9)(x−7)
so x = 7 or x = 9
from this, y = 9 when x = 7 and y = 7 when x = 9
so, the dimension of the rectangle is 9″ by 7″
So finding the rope is kind of like finding the perimeter. Add 61+61+21+21 and you will get 164 feet.
All you have to do is insert whatever they give you into <em>x. </em>So for example they give you f(2) all you do is is insert the two where x is.
