Coordinate plane with quadrilaterals ABCD and EFGH with A at 0 comma 0, B at 2 comma 0, C at 3 comma negative 2, D at negative 1
comma negative 2, E at 2 comma 4, F at 6 comma 4, G at 7 comma 2, and H at 1 comma 2
Are quadrilaterals ABCD and EFGH similar?
Yes, quadrilaterals ABCD and EFGH are similar because a translation of (x + 2, y + 4) and a dilation by the scale factor of 2 from point D′ map quadrilateral ABCD onto EFGH.
Yes, quadrilaterals ABCD and EFGH are similar because a translation of (x + 3, y + 4) and a dilation by the scale factor of 2 from point A′ map quadrilateral ABCD onto EFGH.
No, quadrilaterals ABCD and EFGH are not similar because their corresponding angles are not congruent.
No, quadrilaterals ABCD and EFGH are not similar because their corresponding segments are not proportional.
Are quadrilaterals ABCD and EFGH similar?
Yes, quadrilaterals ABCD and EFGH are similar because a translation of (x + 2, y + 4) and a dilation by the scale factor of 2 from point D′ map quadrilateral ABCD onto EFGH.
Yes, quadrilaterals ABCD and EFGH are similar because a translation of (x + 3, y + 4) and a dilation by the scale factor of 2 from point A′ map quadrilateral ABCD onto EFGH.
No, quadrilaterals ABCD and EFGH are not similar because their corresponding angles are not congruent.
No, quadrilaterals ABCD and EFGH are not similar because their corresponding segments are not proportional.
2 answers:
Answer:
No, quadrilaterals ABCD and EFGH are not similar because their corresponding segments are not proportional
Step-by-step explanation:
Corresponding sides have the same slope, so corresponding angles are congruent.
Side AB is 1/2 the length of side EF; side BC is equal to the length of FG, so corresponding sides are not proportional.
The two quadrilaterals are not similar because their corresponding segments are not proportional (last choice).
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Using the hypergeometric distribution, it is found that there is a 0.7568 = 75.68% probability that neither can wiggle his or her ears.
The people are chosen from the sample without replacement, which is why the <u>hypergeometric distribution</u> is used to solve this question.
Hypergeometric distribution:
The parameters are:
- x is the number of successes.
- N is the size of the population.
- n is the size of the sample.
- k is the total number of desired outcomes.
In this problem:
- 1000 people means that
- 130 can wiggle their ears, thus
- Two are selected, thus
.
The probability that neither can wiggle his or her ears is P(X = 0), thus:
0.7568 = 75.68% probability that neither can wiggle his or her ears.
A similar problem is given at brainly.com/question/24826394