Coordinate plane with quadrilaterals ABCD and EFGH with A at 0 comma 0, B at 2 comma 0, C at 3 comma negative 2, D at negative 1
comma negative 2, E at 2 comma 4, F at 6 comma 4, G at 7 comma 2, and H at 1 comma 2
Are quadrilaterals ABCD and EFGH similar?
Yes, quadrilaterals ABCD and EFGH are similar because a translation of (x + 2, y + 4) and a dilation by the scale factor of 2 from point D′ map quadrilateral ABCD onto EFGH.
Yes, quadrilaterals ABCD and EFGH are similar because a translation of (x + 3, y + 4) and a dilation by the scale factor of 2 from point A′ map quadrilateral ABCD onto EFGH.
No, quadrilaterals ABCD and EFGH are not similar because their corresponding angles are not congruent.
No, quadrilaterals ABCD and EFGH are not similar because their corresponding segments are not proportional.
Are quadrilaterals ABCD and EFGH similar?
Yes, quadrilaterals ABCD and EFGH are similar because a translation of (x + 2, y + 4) and a dilation by the scale factor of 2 from point D′ map quadrilateral ABCD onto EFGH.
Yes, quadrilaterals ABCD and EFGH are similar because a translation of (x + 3, y + 4) and a dilation by the scale factor of 2 from point A′ map quadrilateral ABCD onto EFGH.
No, quadrilaterals ABCD and EFGH are not similar because their corresponding angles are not congruent.
No, quadrilaterals ABCD and EFGH are not similar because their corresponding segments are not proportional.
2 answers:
Answer:
No, quadrilaterals ABCD and EFGH are not similar because their corresponding segments are not proportional
Step-by-step explanation:
Corresponding sides have the same slope, so corresponding angles are congruent.
Side AB is 1/2 the length of side EF; side BC is equal to the length of FG, so corresponding sides are not proportional.
The two quadrilaterals are not similar because their corresponding segments are not proportional (last choice).
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Answer:
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Step-by-step explanation:
Answer:
Length of the building = 30 meters
Step-by-step explanation:
Given:
Length of pole = 5 meters
Length of shadow of pole = 3 meters
Length of shadow of the building = 18 meters
To find length of the building.
Solution:
On drawing the figure of the given situation, we get two similar triangles.
Applying proportionality theorem of similar triangles.
Plugging in the given lengths.
Multiplying both sides by 18.
Thus, length of the building = 30 meters
