Answer:
![\sqrt[5]{2^4}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B2%5E4%7D)
Step-by-step explanation:
Maybe you want 2^(4/5) in radical form.
The denominator of the fractional power is the index of the root. Either the inside or the outside can be raised to the power of the numerator.
![2^{\frac{4}{5}}=\boxed{\sqrt[5]{2^4}=(\sqrt[5]{2})^4}](https://tex.z-dn.net/?f=2%5E%7B%5Cfrac%7B4%7D%7B5%7D%7D%3D%5Cboxed%7B%5Csqrt%5B5%5D%7B2%5E4%7D%3D%28%5Csqrt%5B5%5D%7B2%7D%29%5E4%7D)
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In many cases, it is preferred to keep the power inside the radical symbol.
Answer:
J) 110.88 mm^2
Step-by-step explanation:
height =6.93x2=13.86
Area=13.86x16x0.5=110.88
Answer:
PD = 8
Step-by-step explanation:
PC x PD = PA x PB
3 x PD = 4 x (4 + 2)
3PD = 24
PD = 8
Answer:
2 units
Step-by-step explanation:
Vpyramid = ⅓ x base area x height
70 = ⅓ x base area x 6
70 = 2 x base area
base area = 70/2 = 35 units
Vprism = base area x height
70 = 35 x height
height = 70/35 = 2 Units
Answer:
No it does not make either equation true
Step-by-step explanation:
If you substitute x, (0) and y (4) into the equation and solve, It doesn't end with a true statement.
