9514 1404 393
Answer:
f'(x) = (-6x² -14x -23)/(x² +5x +2)²
f''(x) = (12x³ +42x² +138x +202)/(x² +5x +2)³
Step-by-step explanation:
The applicable derivative formula is ...
d(u/v) = (v·du -u·dv)/v²
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f'(x) = ((-x² -5x -2)(4x +4) -(2x² +4x -3)(-2x -5))/(-x² -5x -2)²
f'(x) = (-4x³ -24x²-28x -8 +4x³ +18x² +14x -15)/(x² +5x +2)²
f'(x) = (-6x² -14x -23)/(x² +5x +2)²
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Similarly, the second derivative is the derivative of f'(x).
f''(x) = ((x² +5x +2)²(-12x -14) -(-6x² -14x -23)(2(x² +5x +2)(2x +5)))/(x² +5x +2)⁴
f''(x) = ((x² +5x +2)(-12x -14) +2(6x² +14x +23)(2x +5))/(x² +5x +2)³
f''(x) = (12x³ +42x² +138x +202)/(x² +5x +2)³
Answer:
the equation only has 1 solution
Step-by-step explanation:
Answer:
c=0.42 pounds
Step-by-step explanation:
You divide one of cost by the pounds to get how much one costs then you plug in the equation Cost= # of pound times 48
The value of 3 in 300 is ten times I hope this helps you tell me if you want ,e to explain
Answer:
(5.4k+7.9m+8.1n) centimeters
Step-by-step explanation:
Given the side length of a triangle;
S1 = (1.3k+3.5m) cm
S2 = (4.1k-1.6n) cm
S3 = (9.7n+4.4m) cm
Perimeter of the triangle = S1+S2 + S3
Perimeter of the triangle = (1.3k+3.5m) + (4.1k-1.6n) + (9.7n+4.4m)
Collect the like terms;
Perimeter of the triangle = 1.3k+4.1k+3.5m+4.4m-1.6n+9.7n
Perimeter of the triangle = 5.4k+7.9m+8.1n
Hence the expression that represents the perimeter of the triangle is (5.4k+7.9m+8.1n) centimeters
