V(t) = 2t^2 - 3t - 3
for an acceleration a(t),
a(t) = d (v(t)) / d t
a(t) = 4t - 3
at t=2
a(2) = 8 - 3
a(2) = 5 feet/s^2
<span>(-yx^2)^2 • -2x^0y^3
= x^4y^2 (-2y^3)
= - 2x^4y^5</span>
Answer:
x = -3
Step-by-step explanation:
The line parallel to x=8 is another vertical line:
x = constant
To make it go through a point with an x-coordinate of -3, the constant must be -3.
Your line is ...
x = -3
Answer:
The correct answer is C, as growth on stock E is bigger from the growth of stock B
Step-by-step explanation:
In order to resolve this problem, we must have in mind that the negative numbers are smaller when they are more distant from 0, and that positive numbers are bigger when they are more distant from 0. So, the biggest number of growth is the one that is more distant from 0.
The correct answer is C, as growth on stock E is bigger from the growth of stock B.
