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2 years ago

Write an equation of the line below. HELP ASAP!!

Mathematics

2 answers:

scZoUnD [109]2 years ago

7 0

Answer: y= x/4+4

Step-by-step explanation:

So we can see the points are (-8,2), (0,4)

Every equation of a line has the equation y=mx+b

substituting the x and y values we get

2= -8m+b

4=0m+b=b

so b=4, and if we put that in the first equation we get m= 1/4.

So the equation of the line will be y= x/4+4

kkurt [141]2 years ago

7 0

Answer:

Step-by-step explanation:

The equation of a straight line can be represented in the slope-intercept form, y = mx + c

Where c = intercept

Slope, m =change in value of y on the vertical axis / change in value of x on the horizontal axis

change in the value of y = y2 - y1

Change in value of x = x2 -x1

y2 = final value of y

y 1 = initial value of y

x2 = final value of x

x1 = initial value of x

From the graph

y2 = 5

y1 = 4

x2 = 4

x1 = 0

Slope, m = (5 - 4)/(4 - 0) = 1/4

To determine the intercept, c, we would substitute m = 1/4, x = 4 and y = 5 into y = mx + c. It becomes

5 = 1/4 × 4 + c

5 = 1 +c

c = 5 - 1 = 4

The equation becomes

y = x/4 + 4

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Suppose that two electronic components in the guidance system for a missile operate independently and that each has a length of

lord [1]

Answer:

The probability density function for the average length of life of the two components is $f(x) = 0.5e^{-0.5x}$

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following probability density:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

Each missile has a length of life governed by the exponential distribution with mean 1 (with measurements in hundreds of hours). Find the probability density function for the average length of life of the two components.

2, each with mean 1 means that $m = 2*1 = 2, \mu = \frac{1}{2} = 0.5$

So the probability density function is:

$f(x) = 0.5e^{-0.5x}$

8 0

2 years ago

PLEASE HELP!

777dan777 [17]

1. 1/10 (3000) = 3000/10 = 300...so 1/10 of 3000 is 300
300/10 = 30...and 300 is 10 times as much as 30

2. 10 times as much as 8 = (10 x 8) = 80
1/10x = 80
x = 80 * 10 = 800
so 1/10 of 800 is 10 times as much as 8

3. 1/10(50,000) = 50,000/10 = 5000
5000/10 = 500
1/10 of 50,000 is 10 times as much as 500

4. 1/10(40,000) = 40,000/10 = 4,000
4000/10 = 400
1/10 of 40,000 is 10 times as much as 400

5. 1/10 (900) = 900/10 = 90
10x = 90
x = 90/10
x = 9
10 times as much as 9 is 1/10 of 900

6. 1/10 (60,000) = 60,000/10 = 6000
10x = 6000
x = 6000/10
x = 600
10 times as much as 600 is 1/10 of 60,000

7. 70 x 10 = 700
1/10x = 700
x = 700 * 10
x = 7000
10 times as much as 700 is 1/10 of 7000

8. 10 x 2000 = 20,000
1/10x = 20,000
x = 20,000 * 10
x = 200,000
10 times as much as 2000 is 1/10 of 200,000

9. 10 times as much as 2000.....2000 x 10 = 20,000
1/10 of what is 20,000.....1/10x = 20,000....multiply both sides by 10, this eliminates the 1/10 on the left side....resulting in 200,000.
so basically, 10 times as much as 2000 = 20,000 and 1/10 of 200,000 = 20,000

6 0

3 years ago

What is the value of X ?

harkovskaia [24]

The sum of all the angle measures is 180 degrees, now lets set up some equations:

$(3x-35)+(x-35)+x = 180\\5x - 70 = 180\\5x = 110\\x = 22$

Thus x = 22

Hope that helps!

3 0

2 years ago

Please help me <br>I need number 8 and 9 please show work and thank you!!!

I am Lyosha [343]

8) We know the bases of the cylinder are 28.27, and that there are two of them. Therefore, the area of the circles is 57.4. Then 207.35- 57.4 = 149.95.

7 0

2 years ago

Find the measure of ∠. Show your work.

solniwko [45]

Answer:

m/angle ABC=47^o

Step-by-step explanation:

we know that

The measure of the external angle is the semi-difference of the arches it covers

m\angle ABC=\frac{1}{2}[arc\ DE-arc\ AC]

substitute the given values

m\angle ABC=\frac{1}{2}[142^o-48^o]

m\angle ABC=47^o

7 0

3 years ago