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3 years ago

Factor 2x^3+4x^2-6x+9

2 answers:

7 0

Try factoring out a 2x from the first 3 terms in the question, like so:

$2x( x^{2} +2x-3)+9$

Now, you can factor the middle quadratic equation and you will have 3 factors plus the constant in the end (the +9). Hope this helps!

Greeley [361]3 years ago

5 0

Answer:factoring out a 2x it was from first 3 terms

Step-by-step explanation:

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What’s 5/6 divided by 5/2 in fraction form

nadya68 [22]

Answera:The answer is 0.3333333333 repeated

Step-by-step explanation:5/6 is 0.8333333 repeated divided by 5/2 which is 2.5 which when divided is 0.333333333 repeated.

4 0

2 years ago

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Solve the equation. Check the solution. 1/2(2x-1)= -1/9 -7/9

Thepotemich [5.8K]

Answer:

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3 years ago

SOMEONE PLS HELP ME WITH THIS: Jack Thomas has an fudge sundae with 450 calories. How long would it take him to burn off the cal

KATRIN_1 [288]

Answer:

It would take him 450 minutes to burn off the calories by sleeping

Step-by-step explanation:

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3 years ago

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A recipe requires 31 cup of milk for each 41 cup of water. How

avanturin [10]

Step-by-step explanation:

here,

31 cup of milk require 41 cup of water.

1 cup of milk require 41/31 cup of water.

so, 41/31 cup of water is required for 1 cup of milk.

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6 0

3 years ago

If f(x) = x2 - 2x and g(x) = 6x + 4 for which value of x does (t +g)(x)=0

Vinil7 [7]

Answer:

-2

Assumption:

Find the value of x such that $(f+g)(x)=0$ .

Step-by-step explanation:

$(f+g)(x)=0$

$f(x)+g(x)=0$

$(x^2-2x)+(6x+4)=0$

Combine like terms:

$x^2+4x+4=0$

This is not too bad too factor on the left hand side since 2(2)=4 and 2+2=4.

$(x+2)(x+2)=0$

$(x+2)^2=0$

So we need to solve:

$x+2=0$

Subtract 2 on both sides:

$x=-2$

Let's check:

$(f+g)(-2)$

$f(-2)+g(-2)$

$((-2)^2-2(-2))+(6(-2)+4)$

$(4+4)+(-12+4)$

$(8)+(-8)$

$0$

0 was the desired output of $(f+g)(x)$ .

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3 years ago