Answer:
E₄ = - 0.85 eV
E₂ = - 3.4 eV
Ephoton = 2.55 eV
Explanation:
The sum of Kinetic Energy (K) and Potential Energy (U) of the Helium atom is equal to the total energy of Helium atom in the specified state N. From Bohr's atomic model, the energy of a hydrogen atom in state N is given as:
En = K + U = (-1/n²)(13.6 eV)
a)
Here,
n = 4
Therefore,
E₄ = (-1/4²)(13.6 eV)
<u>E₄ = - 0.85 eV</u>
<u></u>
b)
Here,
n = 2
Therefore,
E₂ = (-1/2²)(13.6 eV)
<u>E₂ = - 3.4 eV</u>
<u></u>
c)
The energy of photon emitted in the transition from level 4 to level 2 will be equal to the difference in the energy of both levels:
Ephoton = ΔE = E₄ - E₂
Ephoton = - 0.85 eV - (- 3.4 eV)
<u>Ephoton = 2.55 eV</u>
<u></u>
An extensive property is a property of a substance that is dependent on the size or the amount of the substance in a system. Examples are number of moles, volume, energy, entropy, heat capacity, internal energy and mass. This would also be the same definition for extensive values. From the problem statement, the extensive values are the cost and price. These values have units of $ per gram which, obviously, dependent with the mass of the gasoline. The other values like the humidity, air pressure and the hardness are called intensive values since they are independent of the amount of the substance.
Considering both boxes as one body, it would have a total mass of 4.0 kg. By Newton's second law, the 32 N force applies an acceleration <em>a </em>such that
∑ <em>F</em> = 32 N = (4.0 kg) <em>a</em> → <em>a</em> = 8.0 m/s²
and both boxes share this acceleration. (There is no friction, so the given force is the only one involved in the direction of the boxes' motion.)
Now consider just the smaller box. It is feeling the effect of the 32 N push in one direction and, as it comes into contact with the larger box, a normal force that points in the opposite direction. Let <em>n</em> be the magnitude of this normal force; this is what you want to find. By Newton's second law,
∑ <em>F</em> = 32 N - <em>n</em> = (1.0 kg) (8.0 m/s²)
<em>n</em> = 32 N - 8.0 N
<em>n</em> = 24 N
Just to make sure that this is consistent: by Newton's third law, the larger box feels the same force but pointing in the opposite direction. On the smaller box, <em>n</em> opposes the pushing force, so points backward. So from the larger box's perspective, <em>n</em> acts on it in the forward direction. This is the only force acting on the larger box, so Newton's second law gives
∑ <em>F</em> = 24 N = (3.0 kg) (8.0 m/s²)
I have a strong hunch that if you read through pages 184 to 187 in the book,
you'll find each of these statements there, with no blank spaces.
1. negative
2. static
3. electrons
4. repel
5. attract
6. static
7. electric current
8. closed or complete
9. open
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