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3 years ago

Two football players each applied 100 n of force to sack the qb and move him 3 meters downfield. How much work was done?

1 answer:

4 0

<span>We know that the equation for work is W=force x distance, where work is in Joules, force is in Newtons and distance is in meters. In this situation, W= (100*2) x 3 which would result in W=600 J. The work done was 600 Joules.</span>

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The slope of a position-timw graph can be used to find the moving objects.....?

Fofino [41]

Answer:

Velocity

Explanation:

The slope of a position-time graph gives velocity of a moving object.

8 0

3 years ago

Many asteroids are found between mars and which other celestial body?.

Fofino [41]

Answer:

Main Asteroid Belt: The majority of known asteroids orbit within the asteroid belt between Mars and Jupiter, generally with not very elongated orbits. The belt is estimated to contain between 1.1 and 1.9 million asteroids larger than 1 kilometer (0.6 miles) in diameter, and millions of smaller ones.

Explanation:

5 0

3 years ago

How did the coastal mountains form

liubo4ka [24]

Normally its when two tectonic plates hit each other and one plate subducts underneath the other this causes the other plate to be thrust upwards forming mountains

4 0

3 years ago

You decide to travel by car for your holiday visits this year. You leave early in the morning to avoid congestion on the roads.

podryga [215]

Answer:

a) d = 182.08 miles

b) $\overline{v} = 54.5 mph$

Explanation:

a) The distance can be found as follows:

$d_{T} = d_{1} + d_{2} + d_{3}$

$d_{T} = v_{1}*t_{1} + v_{2}*t_{2} + v_{3}*t_{3}$

$d_{T} = 67.4 mph*1.70 h + 0*23.4 min + 54.0 mph*1.25 h = 182.08 miles = 292.9 km$

b) The average speed can be calculated using the following equation:

$\overline{v} = \frac{d_{f} - d_{i}}{t_{f} - t_{i}}$

Where "f" is for final and "i" for initial

$\overline{v} = \frac{182.08 miles - 0 miles}{(1.70 h + 23.4 min*\frac{1 h}{60 min} + 1.25 h) - 0 h} = 54.5 mph$

I hope it helps you!

5 0

3 years ago

Someone help me with letter d. and e. I’m supposed to solve for y.

Bumek [7]

Answer:

$t=\frac{a}{\sqrt{1-\frac{y^2}{c^2}}}\\\frac{y^2}{c^2}=1-\frac{a^2}{t^2}\\y^2=\frac{c^2t^2-c^2a^2}{t^2}\\y=\frac{c}{t}\sqrt{t^2-a^2}$

$t=\frac{a}{\sqrt{1-\frac{v^2}{y^2}}}\\\frac{v^2}{y^2}=1-\frac{a^2}{t^2}\\\\\frac{v^2}{y^2}=\frac{t^2-a^2}{t^2}\\y^2=\frac{v^2t^2}{t^2-a^2}\\y=\frac{vt}{\sqrt{t^2-a^2}}$

7 0

3 years ago