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yarga [219]
3 years ago
13

Two football players each applied 100 n of force to sack the qb and move him 3 meters downfield. How much work was done?

Physics
1 answer:
Helga [31]3 years ago
4 0
<span>We know that the equation for work is W=force x distance, where work is in Joules, force is in Newtons and distance is in meters. In this situation, W= (100*2) x 3 which would result in W=600 J. The work done was 600 Joules.</span>
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Why are all machines not 100% efficient<br> A. Mass<br> B. Gravity <br> C. Friction <br> D. Distance
Anon25 [30]
All machines are not 100% efficient because of <span>C. Friction</span>
7 0
3 years ago
Read 2 more answers
Please help !! In the diagram, q1 = +0.00200 C, q2 = 0.00180 C, and q3 = +0.00830 C. the net force on q2 is zero. how far is q2
VikaD [51]

Answer:

2.03715

Explanation:

32364=8.99\cdot 10^9\cdot \frac{0.00180\cdot 0.00830}{2.03715^2}

4 0
3 years ago
To balance the forces on the box what direction must you push?
ss7ja [257]
The correct answer would be left
3 0
3 years ago
Hey guys.. ans me
Stels [109]

The time taken by the swimmer was 1 hour.

Why?

Since the swimmer is maintaining an angle of 150° while he was swimming, there were two components of the speed (horizontal and vertical). If we want to calculate the time taken by him to cross the river, we need to calculate the vertical speed and consider that the flow's speed is compensated by his horizontal speed.

We can calculate both components of the speed using the following formula:

HorizontalSpeed=Speed*Cos(150\°)\\\\VerticalSpeed=Speed*Sin(150\°)

Now, calculating we have:

HorizontalSpeed=2\frac{Km}{h} *Cos(150\°)=-\sqrt{3} \frac{Km}{h} \\\\VerticalSpeed=2\frac{Km}{h} *Sin(150\°)=1\frac{Km}{h}

Therefore, we have that the horizontal speed is compesating the flow's speed while his vertical speed is used to cross the river which is 1 Km wide.

Hence, we have that the tame taken is:

Time=\frac{RiverWidth}{VerticalSpeed}=\frac{1Km}{1\frac{Km}{h} } =1h

Have a nice day!

7 0
3 years ago
Example No. 10
Alexxx [7]

The force constant of the spring is determined as 14,222.2 N/m.

<h3>Force constant of the spring</h3>

Apply the principle of conservation of energy,

K.E = U

where;

  • K.E kinetic energy of the elevator
  • U is elastic potential energy of the spring

¹/₂mv² = ¹/₂kx²

mv² = kx²

k = mv²/x²

Where;

  • m is mass of the elevator
  • v is speed
  • x is compression of the spring

k = (2000 x 8²)/(3²)

k = 14,222.2 N/m

Thus, the force constant of the spring is determined as 14,222.2 N/m.

Learn more about force constant here: brainly.com/question/1968517

#SPJ1

5 0
2 years ago
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