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2 years ago

Two football players each applied 100 n of force to sack the qb and move him 3 meters downfield. How much work was done?

1 answer:

4 0

<span>We know that the equation for work is W=force x distance, where work is in Joules, force is in Newtons and distance is in meters. In this situation, W= (100*2) x 3 which would result in W=600 J. The work done was 600 Joules.</span>

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A student throws a water balloon vertically downward from the top of a building. The balloon leaves the thrower's hand with a sp

dusya [7]

from the question you can see that some detail is missing, using search engines i was able to get a similar question on "https://www.slader.com/discussion/question/a-student-throws-a-water-balloon-vertically-downward-from-the-top-of-a-building-the-balloon-leaves-t/"

here is the question : A student throws a water balloon vertically downward from the top of a building. The balloon leaves the thrower's hand with a speed of 60.0m/s. Air resistance may be ignored,so the water balloon is in free fall after it leaves the throwers hand. a) What is its speed after falling for 2.00s? b) How far does it fall in 2.00s? c) What is the magnitude of its velocity after falling 10.0m?

Answer:

(A) 26 m/s

(B) 32.4 m

(C) v = 15.4 m/s

Explanation:

initial speed (u) = 6.4 m/s

acceleration due to gravity (a) = 9.9 m/s^[2}

time (t) = 2 s

(A) What is its speed after falling for 2.00s?

from the equation of motion v = u + at we can get the speed

v = 6.4 + (9.8 x 2) = 26 m/s

(B) How far does it fall in 2.00s?

from the equation of motion $s=ut+0.5at^{2}$ we can get the distance covered

s = (6.4 x 2) + (0.5 x 9.8 x 2 x 2)

s = 12.8 + 19.6 = 32.4 m

c) What is the magnitude of its velocity after falling 10.0m?

from the equation of motion below we can get the velocity

$v^{2} = u^{2} + 2as\\v^{2} = 6.4^{2} + (2x9.8x10)\\V^{2} = 236.96\\v = \sqrt{236.96}$

v = 15.4 m/s

7 0

3 years ago

Chanice drives her scooter 7 kilometers north. she stops for lunch and then drives 5 kilometers and then 1 km east again. what d

lord [1]

Distance covered is given as follows

1). 7 km North

2). 5 km North

3). 1 km East

Now total distance covered will be given as

$d = d_1 + d_2 + d_3$

$d = 7 km + 5 km + 1 km$

$d = 13 km$

Now in order to find the displacement we will show all with their directions

$\vec d_1 = 7 + 5 = 12 km$ towards North

$\vec d_2 = 1 km$ towards East

So total displacement is

$\vec d = \vec d_1 + \vec d_2$

$\vec d = 12 \hat j + 1 \hat i$

so net displacement will be

$d = \sqrt{12^2 + 1^2} = 12.04 km$

so displacement is 12.04 km

6 0

3 years ago

The velocity of sound on a particular day outside is 331 meters/second. What is the frequency of a tone if it has a wavelength o

N76 [4]

Frequency = (speed) / (wavelength)

Frequency = (331 m/s) / (0.6 m) = 551.7 Hz

3 0

3 years ago

Two horses are side by side on a carousel. Which has a greater tangential speed the one closer to the center or the one farther

photoshop1234 [79]

Answer:

The horse father from the center has a greater tangential speed. Although both horses complete one circle in the same time period, the one farther from the center covers a greater distance during that same period.

Explanation:

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2 years ago

Sound waves can be modeled by the equation of the form y=20sin(3t+theta). Determine what type of interference results when sound

Mariulka [41]

Answer:

go to the link quizzlet it will give you tha answer

Explanation:

4 0

2 years ago