Answer:
For carbon 12
ΔV1 = 2265.31 V
ΔV2 = 362.5 V
For carbon 14
ΔV1 = 1941.7 V
ΔV2 = 310.67 V
Explanation:
The complete explanations are given in the attachment below. The formulae for the accelerating potential ΔV1 and ΔV2 are derived and the necessary parameters are substituted into the derived equations.
The best and most correct answer among the choices provided by your question is the third choice or letter C.
<span>The speed of sound in steel is greater than it is in air because steel is more dense than air.</span>
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Answer:
Stationary front
Explanation:
A stationary front is usually defined as a front when both the warm as well as cold front does not move and remain stationary. It is because the force exerted by both the air masses against each other is not so high to displace one another. In this case, the wind blows parallel instead of blowing perpendicular to the front.
Generally, in weather maps, the stationary front is shown by the alternate use of blue triangles and red semi-circles, where the triangle faces the warm front and the semi-circle faces the cold front.
The field lines spread apart as we move away from the charge, and they point away from the charge
Explanation:
The electric field produced by a single-point positive charge is a radial field, whose strength is given by the equation
where
k is the Coulomb's constant
Q is the magnitude of the charge
r is the distance from the charge at which the field is calculated
There are two pieces of information given by the field lines shown in the graph:
- The spacing between the lines gives an indication of the strength of the field: the closer to each other they are, the stronger the field. In this case, as we move away from the charge, the spacing between the lines increases, and this means that the field becomes weaker (in fact, it follows an inverse square law,
- The direction of the lines gives the direction of the electric field, which points away from the central charge. This is because the direction of the electric field corresponds to the direction of the force that a positive test charge would feel when immersed in the electric field: in this case, if we place a positive test charge in this field, then it would get repelled away from the central charge (remember that the electric force between two positive charges is repulsive), and therefore, the direction of the electric field is away from the central charge.
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Answer:
The answer is E. Decrease, increase, decrease
Explanation:
The pressure within the tire wall is a result of the molecules of air colliding with the walls of the tire, if there is a leakage that means some or all of the air molecules will escape resulting in a decrease in the collision between the molecules and the tire wall which means the pressure decreases within the walls which also translates to a decrease in pressure exerted by the tire on the ground surface.
Before the leakage, the tire walls are kept tensed due to the internal pressure exerted by the air molecules. When the leakage occurs the air molecules escape and this makes the tire loose its firm upright shape thereby falling to the floor and creating an increase in the area of contact between the tire and the floor surface.
The force exerted on the floor by the tire is proportional to the the pressure exerted and the surface area through which this force is applied, though the pressure is seen to decrease and the surface area seen to increase, one must consider the weight loss due to the air molecules that escapes which causes the force to decrease.
