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EastWind [94]
3 years ago
6

Write the quadratic function for the parabola having vertex(4,2) and passing through the point (1,11)

Mathematics
1 answer:
Zigmanuir [339]3 years ago
3 0
So the function we are looking for should look like f(x)=a(x-1)2-2, and since the parabola passes through (4,5), we have 5=a(4-1)2-2, which means 5=9a-2, so a = (7/9) and f(x) = (7/9)(x-1)2-2.
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0x has no value they're just putting that in there to trip you up. Also you can view the graph on Desmos graphing calc online to see the minimum value of this function.

x is positive so parabola opens up: meaning minimum value

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