A=p（1+rt） solve r answer
1 answer:
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Answer:
A) Equation of line is 3X - 2Y = 11
B) Equation of line is Y = X + 1
C) Equation of line is Y - 7 = 0
Equation of line , point (3 , -1) and slop is 3X - 2Y = 11
Step-by-step explanation:
Given equation of line as 2x + 3y = 5
slove of this line (m1) = -
Now another line passes through point (3 , -1) having slop (m2)
Both lines are parallel to each other, i.e (m1) × (m2) = - 1
So slop of second line (m2 ) =
(m2) =
(m2) =
Now eq of line with point (3 , -1) and slop (m2)
Y- y1 = (m2)( X - x1)
Or, Y +1 = (X - 3)
i.e 2Y + 2= 3X - 9
∴ Equation of line is 3X - 2Y = 11 Answer
B) Given points as ( 5,6) and (3 , 4)
Slop (m) = =
= 1
So the equation of line is
Y- y1 = (m)( X - x1)
Y - 6 = (1) (X - 5)
i.e Equation of line is Y = X + 1 Answer
C) Given points as ( 0, 7) , (0 , -8)
Slop (m) with co-ordianate =
Or, =
=0
Hence equation of line is Y - 7 = 0 Answer