27 I think or something close to that hope that helps
Answer:
x-intercept = 12, y-intercept = 4
Step-by-step explanation:
To find the x and y intercept, substitute 0 in for both values.
<u>Substitute 0 into x:</u>
2(0) + 6y = 24
6y = 24
<u>Divide each side by 6:</u>
y = 4
<u>Substitute 0 into y:</u>
2x + 6(0) = 24
2x = 24
<u>Divide each side by 2:</u>
x = 12
Answer:
Both the parts of this question require the use of the "Intersecting Secant-Tangent Theorem".
Part A
The definition of the Intersecting Secant-Tangent Theorem is:
"If a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment."
This, when applied to our case becomes, "The length of the secant RT, times its external segment, ST, equals the square of the tangent segment TU".
Mathematically, it can be written as:
Part B
It is given that RT = 9 in. and ST = 4 in. Thus, it is definitely possible to find the value of the length TU and it can be found using the Intersecting Secant-Tangent Theorem as:
Thus,
Thus the length of TU=6 inches
A= 20 cause 5-2=3 and if the top is 23 it has to be 20
Answer:
There is a decreasing pattern the farther they are the less likely hit the target.
Step-by-step explanation: