All categories

4 years ago

Use a graphing calculator or spreadsheet software to solve 4x + y + z = 1 8x – 4y – 7z = 2 5y + 9z = 3 using matrices.

1 answer:

4 0

Put the three equation in the matrice for as I do then take it to a reduced row echelon form, then you will see if he solution is trival, infinitly manay solution ot if it has a definite solution.

Download docx

You might be interested in

Which is bigger 5/8 or 0.58

Luden [163]

Hello!

To compare the two, we must convert 5/8 to a decimal. We'll do that buy dividing the numerator by the denominator.

5 ÷ 8 = 0.625

Compare the two decimals.

0.625 vs. 0.580

So, 5/8 is obviously bigger than 0.58.

7 0

3 years ago

(hg^(-3))/(w^(-4) k^0 )

Svetlanka [38]

One may note you never quite asked anything, now, assuming simplification,

$\bf ~~~~~~~~~~~~\textit{negative exponents}\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}
\\\\
-------------------------------\\\\
\cfrac{hg^{-3}}{w^{-4}k^0}\implies \cfrac{hw^4}{g^3(1)}\implies \cfrac{hw^4}{g^3}$

4 0

3 years ago

PLEASE HELP why isnt 3,4 , 5,10 ,3,12 a function

myrzilka [38]

Functions have one output for every input. So that means one x-coordinate for one y-coordinate. In this case, (3,4) and (3,12) have the same x-coordinate, so it can't be a function.

3 0

3 years ago

A golf retailer purchases its clubs from a wholesaler at $44 per club. It sells the same clubs to golfers at $75 per club. What

emmainna [20.7K]

Answer:

70.45%

Step-by-step explanation:

The markup is $75 -44 = $31. As a percentage of the wholesale price, that is ...

$31/$44 × 100% ≈ 70.45%

3 0

3 years ago

Let C be the boundary of the region in the first quadrant bounded by the x-axis, a quarter-circle with radius 9, and the y-axis,

rewona [7]

Solution :

Along the edge $C_1$

The parametric equation for $C_1$ is given :

$x_1(t) = 9t , y_2(t) = 0 \ \ for \ \ 0 \leq t \leq 1$

Along edge $C_2$

The curve here is a quarter circle with the radius 9. Therefore, the parametric equation with the domain $0 \leq t \leq 1$ is then given by :

$x_2(t) = 9 \cos \left(\frac{\pi }{2}t\right)$

$y_2(t) = 9 \sin \left(\frac{\pi }{2}t\right)$

Along edge $C_3$

The parametric equation for $C_3$ is :

$x_1(t) = 0, \ \ \ y_2(t) = 9t \ \ \ for \ 0 \leq t \leq 1$

Now,

x = 9t, ⇒ dx = 9 dt

y = 0, ⇒ dy = 0

$\int_{C_{1}}y^2 x dx + x^2 y dy = \int_0^1 (0)(0)+(0)(0) = 0$

And

$x(t) = 9 \cos \left(\frac{\pi}{2}t\right) \Rightarrow dx = -\frac{7 \pi}{2} \sin \left(\frac{\pi}{2}t\right)$

$y(t) = 9 \sin \left(\frac{\pi}{2}t\right) \Rightarrow dy = -\frac{7 \pi}{2} \cos \left(\frac{\pi}{2}t\right)$

Then :

$\int_{C_1} y^2 x dx + x^2 y dy$

$=\int_0^1 \left[\left( 9 \sin \frac{\pi}{2}t\right)^2\left(9 \cos \frac{\pi}{2}t\right)\left(-\frac{7 \pi}{2} \sin \frac{\pi}{2}t dt\right) + \left( 9 \cos \frac{\pi}{2}t\right)^2\left(9 \sin \frac{\pi}{2}t\right)\left(\frac{7 \pi}{2} \cos \frac{\pi}{2}t dt\right) \right]$