The values in the the range is called the
2 answers:
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Answer:
The probability that it came from A, given that is defective is 0.362.
Step-by-step explanation:
Define the events:
A: The element comes from A.
B: The element comes from B.
C: The element comes from C.
D: The elemens is defective.
We are given that P(A) = 0.25, P(B) = 0.35, P(C) = 0.4. Recall that since the element comes from only one of the machines, if an element is defective, it comes either from A, B or C. Using the probability axioms, we can calculate that
Recall that given events E,F the conditional probability of E given F is defined as
, from where we deduce that
.
We are given that given that the element is from A, the probability of being defective is 5%. That is P(D|A) =0.05. Using the previous analysis we get that
We are told to calculate P(A|D), then using the formulas we have
Let be a sequence that converges to
. This means for any
, there is some
such that
for all
. From this inequality we see that
, so it follows that
.
On the other hand, let be a sequence that converges to 0. This means
for all large enough
, and we get the simpler inequality for free,
, so it follows that
.