Question

QUICK QUESTION!!!! PLEASE HELP!!!

Answer 1

Answer:

The probability that she rolls a number greater that 4 or a 2 = $\frac{1}{2}$ or 50%

Step-by-step explanation:

Given:

A six sided number cube is rolled labelled from 1 to 6.

To find the probability that she rolls a number that is greater than 4 or a 2.

Solution:

The possible outcomes of rolling a six-sided cube are:

{1,2,3,4,5,6}

$n(U)=6$

Event A:

The favorable outcomes greater than 4 are:

{5,6}

$n(A)=2$

Probability of event  A to occur = $\frac{n(A)}{n(U)}=\frac{2}{6}$

Event B:

The favorable outcome is a 2

{2}

$n(B)=1$

Probability of event  B to occur = $\frac{n(B)}{n(U)}=\frac{1}{6}$

We find that the two events are mutually exclusive as they have no common outcomes.

Thus, the probability that event A or B occurs ( P(AUB) ) can be given as:

⇒ $\frac{2}{6}+\frac{1}{6}$

Since denominators same, so we add the numerators.

⇒ $\frac{3}{6}$

Reducing it to simpler fraction:

⇒ $\frac{1}{2}$     (Answer)

Thus, the probability that she rolls a number greater that 4 or a 2 = $\frac{1}{2}$ or 50%