Since the addition of the H2O in the last step of hydroboration is anti-Markovnikov, the starting material is 1-pentyne.
The addition of H2 to C5H8 yields an alkene when a Lindlar catalyst is used. Recall that the Lindlar catalysts poisons the process so that the addition do not go on to produce an alkane.
When hydroboration is carried out on the alkene, we are told that a primary alcohol was obtained. We must note that in the last step of hydroboration, water is added in an anti- Markovnikov manner to yield the primary alcohol. Hence, the starting material must be 1-pentyne as shown in the image attached.
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I think it’s A but, don’t come at me if I’m wrong. Btw I read over it multiple times so this isn’t a random guess. Good luck tell me if you got it right
Here this might help you added the website link:
https://phet.colorado.edu/sims/html/build-an-atom/latest/build-an-atom_en.html
Answer:
Explanation:
Density:
Density is equal to the mass of substance divided by its volume.
Units:
SI unit of density is Kg/m3.
Other units are given below,
g/cm3, g/mL , kg/L
Formula:
D=m/v
D= density
m=mass
V=volume
Symbol:
The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.
Given data:
Mass = 1.060 g
Volume = 1.0 mL
Density in correct number of significant figures= ?
Solution:
d = m/v
d = 1.060 g / 1.0 mL
d = 1.06 g/ mL
The density 1.06 g/mL contain three significant figures Henry should report it 1.1 g/mL having the only one digit after decimal because in given values 1.060 and 1.0 the least number of significant figures after the decimal is 1 that's why the final result must have one significant figure after decimal.
Phosphorus has 5 valence
valence electrons is located to their group#
yes because of TAVE available valence electrons
